SELECT department_name, cou FROM
(
SELECT department_name, count(student_id) AS cou
FROM department d NATURAL JOIN student s
GROUP BY department_name
)
GROUP BY department_name HAVING cou=max(cou);
答案 0 :(得分:0)
首先关闭 - 避免自然加入。这很危险。谷歌的原因。 您收到的消息是因为您有OUTER选择的GROUP BY,但您在select子句中没有聚合函数。
看起来你可能完全失去外部选择并将HAVING子句放在内部选择上。
答案 1 :(得分:0)
SELECT * FROM (
SELECT department_name, count(student_id) AS cou
FROM department d
JOIN student s USING (student_id)
GROUP BY department_name
ORDER BY count(student_id) DESC )
WHERE rownum = 1