我有两张表格如下
NameId Name
11 Ancillary
22 Reviews
33 Audit
44 Logging
id NameId CountyId
51 11 1
52 11 1
53 11 2
54 22 2
55 22 3
56 33 3
57 33 3
结果应该是与县相关联的姓名总数,如下所示。如果有超过4个名称,则Nameid可以是动态意义查询应该能够自动显示计数而无需硬编码行名称。同时计算最后每行的总数。
CountyId AncillaryCount ReviewsCount AuditCount LoggingCount Total
1 2 0 0 0 2
2 1 1 0 0 2
3 0 1 2 0 3
答案 0 :(得分:1)
IF OBJECT_ID('Tempdb..#Temp') IS NOT NULL
Drop table #Temp
DECLARE @TabA Table (NameId INT,Name Varchar(100))
INSERT INTO @TabA
SELECT 11,'Ancillary' Union all
SELECT 22,'Reviews' Union all
SELECT 33,'Audit' Union all
SELECT 44,'Logging'
DECLARE @TabB Table (id INT, NameId INT,CountyId INT)
INSERT INTO @TabB
SELECT 51,11,1 UNION ALL
SELECT 52,11,1 UNION ALL
SELECT 53,11,2 UNION ALL
SELECT 54,22,2 UNION ALL
SELECT 55,22,3 UNION ALL
SELECT 56,33,3 UNION ALL
SELECT 57,33,3 UNION ALL
SELECT 57,44,3
SELECT B.CountyId,
A.Name,
COUNT(A.Name) Over(Partition by B.CountyId,A.Name Order by B.CountyId) AS CountName
INTO #Temp from @TabA A
LEFT join @TabB B
On b.NameId=a.NameId
DECLARE @Coulmn nvarchar(max),
@Coulmn2 nvarchar(max),
@SumCoulmn nvarchar(max),
@Sql nvarchar(max)
SELECT @Coulmn=STUFF((SELECT DISTINCT ', '+ '['+ Name +']' From #Temp
FOR XML PATH ('')),1,1,'')
SELECT @SumCoulmn=STUFF((SELECT DISTINCT ', '+ + Name +'Count' From #Temp
FOR XML PATH ('')),1,1,'')
SET @SumCoulmn= '('+REPLACE(@SumCoulmn,',',' + ')+')'
SELECT @Coulmn2=STUFF((SELECT DISTINCT ', '+ 'ISNULL(' + Name + ',''0'')' +' AS ['+Name +'Count]' From #Temp
FOR XML PATH ('')),1,1,'')
SET @Sql='SELECT *,'+@SumCoulmn+ ' AS Total From
(
SELECT CountyId,'+@Coulmn2+ ' From
(
SELECT * From #Temp
)As Src
PIVOT
(
MAX(CountName) FOR Name IN ('+ @Coulmn +')
)Pvt
)Dt
'
Print @Sql
Exec(@Sql)