可以从ItemizedOverlay类启动Intent吗? (mapview项目)

时间:2010-12-15 14:12:14

标签: android android-intent android-mapview itemizedoverlay

我有一个mapview,带有itemizedoverlays,与Android开发人员指南的示例完全相同:http://developer.android.com/resources/tutorials/views/hello-mapview.html

在itemizedoverlay上,我有一个个性化的对话框,带有一个按钮。一切都很好,直到这里,但现在我有问题尝试添加按钮的功能。我需要按钮开始是一项新活动,但我无法实现这一点....¿为什么?因为在这一行:i = new Intent (NyItemizedOverlay.class, Locate.class);我有当前的Intent类作为第一个参数,而目标intent类在第二个参数。

MyItemizedOverlay不是Intent类...它是ItemizedOverlay扩展,然后当我尝试启动intent时它不​​会编译,我试图将普通类作为第一个参数传递,并且它需要一个intent类。我必须把启动器类,但启动器类不是一个意图:S

如果我尝试在第一个参数上放置另一个intent类,我收到此错误:No enclosing instance of the type AllActivity is accessible in scope ....(AllActivity是我的应用程序的公共活动类)

我如何解决这个问题?

完整代码:

public class MyItemizedOverlay extends ItemizedOverlay {


 private ArrayList<OverlayItem> mOverlays = new ArrayList<OverlayItem>();
 private ArrayList<String> permissions = new ArrayList<String>();
 private Context mContext;

 public MyItemizedOverlay(Drawable defaultMarker) {
  super(boundCenterBottom(defaultMarker));
 }

 protected OverlayItem createItem(int i) {
   return mOverlays.get(i);
 }

 public int size() {
   return mOverlays.size();
 }

 public void addOverlay(OverlayItem overlay) {
     mOverlays.add(overlay);
     populate();
 }
 public void addOverlay(OverlayItem overlay,String permission) {
     mOverlays.add(overlay);
     permissions.add(permission);
     populate();
 }

 public MyItemizedOverlay(Drawable defaultMarker, Context context) {
    //super(defaultMarker);
    super(boundCenterBottom(defaultMarker));
    mContext = context;
 }
 public void clear()
 {
  mOverlays.clear();
  permissions.clear();//lista de permisos de cada usuario, ya que hay dos campos, el email (snippet) y el permission, una lista.
 }

 protected boolean onTap(int index) {
   try{
    OverlayItem item = mOverlays.get(index);
    if (permissions.size()==0)
    {     
     AlertDialog.Builder dialog = new AlertDialog.Builder(mContext);
     dialog.setTitle(item.getTitle());
     dialog.setMessage(item.getSnippet());
     dialog.show();
    }
    else
    {

    //set up dialog
    Dialog dialog = new Dialog(mContext);
    dialog.setContentView(R.layout.personal_dialog);
    dialog.setTitle(item.getTitle());
    dialog.setCancelable(true);
    //there are a lot of settings, for dialog, check them all out!


    //set up text
    TextView DialogEmail = (TextView) dialog.findViewById(R.id.DialogEmail);
    TextView DialogPermission = (TextView) dialog.findViewById(R.id.DialogPermission);
    DialogEmail.setText(item.getSnippet());
    DialogPermission.setText(permissions.get(index));

    final String userName=item.getTitle();
    final String email=item.getSnippet();
    final int cont=index;
    //set up button
    Button button = (Button) dialog.findViewById(R.id.DialogButton);
    button.setOnClickListener(new OnClickListener() {
     @Override
     public void onClick(View v) {
      //do something
      Bundle bundle = new Bundle(); //bundle is like the letter
      bundle.putString ("user",userName ); //arg1 is the keyword of the txt, arg2 is the txt
            bundle.putString ("email", email);
            bundle.putString ("permission", permissions.get(cont));
            Intent i=null;

             i = new Intent (MyItemizedOverlay.class, Locate.class);

            i.putExtras(bundle);
            startActivity(i);
     }
    });
    //now that the dialog is set up, it's time to show it    
    dialog.show();

    }
   }catch(Exception e){}
   return true;
 }


}

3 个答案:

答案 0 :(得分:4)

Intent javadoc清楚地表明第一个arg必须是一个Context(由activity扩展),第二个arg是你尝试启动的活动的类。在你的情况下,你需要做:

Intent intent = new Intent(mContext, AllActivity.class);
mContext.startActivity(intent);

答案 1 :(得分:3)

通常,Intent将其构造函数Context作为第一个参数,而Activity类作为第二个参数。所以,请执行以下操作:

Intent intent = new Intent(mContext, AllActivity.class);
mContext.startActivity(intent);

答案 2 :(得分:0)

对于意图构造函数,它应该传递实现此类的应用程序包的A Context,检查this。这不是意图 它必须是一些Activity,比如使用你的MyItemizedOverlay类MyClass。最好的办法是声明static ContextmyContext并在myContext = MyClass.this;中将其值声明为onCreate。然后你可以像这样声明意图

 new Intent (MyClass.myContext , Locate.class);