Question

我正在使用Xcode 8.3.2中的Swift 3.0和IOS 10开发应用程序。但是当我尝试从此APIRest（http://schematic-ipsum.herokuapp.com/）中检索JSON时，我遇到了问题。问题是什么？或者你将如何打电话。如果您需要有关代码的更多信息，请告诉我，但基本上，我只想打电话到该页面来恢复传记。

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我的代码是：

import AlamofireDomain
import Alamofire
import ObjectMapper

class AuthorDAO : SimpleDAO {
    func getBiography(_ parameters: Dictionary<String, Int>,
                      callbackFuncionOK:    @escaping 
                     (PropertiesAuthorModel)->(),
                      callbackFunctionERROR: @escaping (Int,NSError)->()) {


        let ulr = NSURL( string: "http://schematic-ipsum.herokuapp.com/" as String)
        let request = NSMutableURLRequest(url:  ulr! as URL)
        request.httpMethod = "POST"
        request.setValue("application/json", forHTTPHeaderField: "Constent-Type")
        let data = try! JSONSerialization.data(withJSONObject: parameters, options: JSONSerialization.WritingOptions.prettyPrinted)

        let json = NSString(data: data, encoding: String.Encoding.utf8.rawValue)
        if let json = json {
            print(json)
        }

        request.httpBody = json!.data(using: String.Encoding.utf8.rawValue)


        Alamofire.request(request as URLRequest)
            .responseJSON { response in
            if response.result.isSuccess{
                if let status = response.response?.statusCode {
                    switch(status){
                    //MARK: CONTROL ON DIFERENTS KINDS OF RESPONSES ON SERVER
                    case 200:
                        if let value = response.result.value {
                            let biographyResponse = Mapper<PropertiesAuthorModel>().map(JSONObject: value)
                            callbackFuncionOK(biographyResponse!)
                        }

                    //case 400: {} ..., case 404: {} ...
                    default:
                        break
                    }
                }
            }

            //MARK: ERROR ON SERVER
            else {
                var statusCode = -1
                if let _response = response.response {
                    statusCode = _response.statusCode
                }
                var nsError: NSError = NSError(domain: Constants.UNKNOWN_HTTP_ERROR_MSG,
                                               code: Constants.UNKNOWN_HTTP_ERROR_ID,
                                               userInfo: nil)
                if let _error = response.result.error {
                    nsError = _error as NSError
                }
                callbackFunctionERROR(statusCode,nsError)
            }
        }
}

错误是：“Error Domain = Alamofire.AFError Code = 4”由于错误，无法序列化JSON：由于格式不正确，无法读取数据。“400 “

问题是它没有进入“if response.result.isSuccess {”，因为响应的结果是“nil”并直接进入“else”。显示我评论过的错误。是不是因为我必须在httpBody请求中发送JSON格式？我该怎么办？

Answer 1

你的问题应该更清楚。 “问题是什么？”没有更多信息就无法回答。

要发出HTTP请求，请查看Alamofire，一个用Swift编写的HTTP网络库：https://github.com/Alamofire/Alamofire

Alamofire.request("https://httpbin.org/get").responseJSON { response in
    print(response.request)  // original URL request
    print(response.response) // HTTP URL response
    print(response.data)     // server data
    print(response.result)   // result of response serialization

    if let JSON = response.result.value {
        print("JSON: \(JSON)")
    }
}

Swift 3 - 创建简单请求方法的问题POST（URLRequestVonvertible）

1 个答案: