我之前尝试过问这个问题,但没有解释得好。我会再试一次,我有一个字典,可以获取和设置图像的字符串,并列出获取字符串。字典项存储在listBox中,当我双击它设置的项目到另一个comboBox时。我想单击一个将遍历字典的按钮,如果它们匹配字典中的任何内容,它将存储在listView中。我不想要图像,只需要字符串名称和价格,这里是类和字典:
$resultLoad = getUserDetails($db,"photo","user_details",$_SESSION['theUserskey']);
$photosName = $resultLoad['photo'];
$file = 'photos/' . $photosName;
// Check mime type
$mime = mime_content_type($file);
$validMimes = ['image/jpeg', 'image/gif', 'image/png', 'image/svg+xml'];
// Refuse to serve invalid files
if (!in_array($mime, $validMimes)) {
die('Invalid file type');
}
header('Content-Type:' . $mime);
header('Content-Length: ' . filesize($file));
readfile($file);
exit();
你们觉得我应该上新课吗?我在其他许多人中尝试过这个:
class BookTitle
{
public string ImageTitle { get; set; }
public List<string> Prices { get; }
public BookTitle(string imageTitle, params string[] prices)
{
ImageTitle = imageTitle;
Prices = new List<string>(prices.Length);
Prices.AddRange(prices);
}
}
private Dictionary<string, BookTitle> prices = new Dictionary<string, BookTitle>
{
{ "Visual Basic", new BookTitle("vb.png", "$55") },
{ "Java", new BookTitle("java.png", "$45") },
{ "C#", new BookTitle("c#.png", "$75") },
{ "LAN Networks", new BookTitle("lan.png", "$68") },
{ "Windows Networking", new BookTitle("windows.png", "$49") },
{ "More About Networking", new BookTitle("more.png", "$54") },
{ "Web Programming", new BookTitle("web.png", "$67") },
{ "JavaScript", new BookTitle("javascript.png", "$64") },
{ "ASP", new BookTitle("asp.png", "$50") }
};
答案 0 :(得分:1)
你可以这样做,
def calculate(param: Similarity) = {
println("hi")
}
答案 1 :(得分:1)
@Sajeetharan我会接受你的回答,因为它非常有帮助,让我走上了正确的轨道。我最终做到了这一点:
private void finalizeButton_Click(object sender, EventArgs e)
{
foreach (var comboItem in cartComboBox.Items)
{
if (prices.Keys.Contains(comboItem.ToString()))
{
BookTitle bt = prices[comboItem.ToString()];
ListViewItem list = cartListView.Items.Add(comboItem.ToString());
foreach (var p in bt.Prices)
{
list.SubItems.Add(p);
}
}
}
}