Question

我想用Js / HTML获取一些图像的URL： img class =＆＃34; img-responsive＆＃34; ID =＆＃34; Q72D2600000-MDYI＆＃34; SRC =＆＃34; HTTPS：？//s7d5.scene7.com/is/image/Guess/Q72D2600000-MDYI $ $ 2014_G_xxlarge＆＃34; ALT =＆＃34; Q72D2600000-MDYI＆＃34; /＆GT;
寻找能够检测图片网址的解决方案。所以输出将是：的 https://s7d5.scene7.com/is/image/Guess/Q72D2600000-MDYI？$ $ 2014_G_xxlarge

Answer 1

以下代码可能有帮助

$html = '<img class="img-responsive" id="Q72D2600000-MDYI" src="https://s7d5.scene7.com/is/image/Guess/Q72D2600000-MDYI?$2014_G_xxlarge$" alt="Q72D2600000-MDYI" />';
preg_match('/<img\s.*?\bsrc="(.*?)".*?>/si', $html, $matches);

$image_src = $matches[1];

echo $image_src;

输出

https://s7d5.scene7.com/is/image/Guess/Q72D2600000-MDYI?$2014_G_xxlarge$

正则表达式获取源代码的图像URL

1 个答案: