Question

我是regex的新手，正在尝试解决以下问题。

输入字符串 - String that has a path as /Users/MyName/moreofPath/ with additional text

输出字符串 - String that has a path as "$relativePath/moreofPath/" with additional text

句子中的绝对路径由

识别

1）/Users/MyName开始的地方

2）在任何其他特殊字符或空格结束之前的最后/

这应该用引号中的相对路径替换。有人可以帮我找到正确的正则表达式。

Answer 1

因为它是所有Python，我会做这样的事情：

import re

thestring = "String that has a path as /Users/MyName/moreofPath/evenmore/ with additional text"
regex = "(.*?)/Users/MyName/(.*/)"
thestring = re.sub(regex, r'\1"$relativePath/\2"' , thestring)
print (thestring)

输出：

String that has a path as "$relativePath/moreofPath/evenmore/" with additional text

我正在做的是抓住比赛中的比赛并替换替换比赛。请注意。*使其贪得心up直到最后/

Answer 2

使用匹配任何路径的正则表达式跟随用户名，只要它不是空格

import re
input_string = "String that has a path as /Users/MyName/moreofPath/ with additional text"
output_string = re.sub(r'/Users/MyName([^\s]*)', r'"$relativePath\1"', input_string)
# 'String that has a path as "$relativePath/moreofPath/" with additional text'

Python Regex将文本中的绝对路径替换为引号中添加的相对路径

2 个答案: