我正在尝试创建一个程序，允许用户添加尽可能多的数字对，首先通过用户输入询问他们想要完成多少总和（添加2个数字），然后创建2个用户输入的任何大小的数组，然后要求用户在一行上输入他们想要添加的每对数字，并将第一个值存储在一个数组中，将第二个值存储在第二个数组中。每个输入。这就是我被卡住的地方，我不知道如何将用户输入作为每行的两个int值并将它们存储在每个数组的相应索引中以便稍后添加。请看下面的代码：
import java.util.Scanner;
public class SumsInLoop {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the amount of sums you would like to calculate: ");
int n = sc.nextInt();
int a[] = new int[n];
int b[] = new int[n];
String[] input = new String[2];
System.out.println("Please enter the values you would like to sum as pairs of two numbers: ");
for (int i = 0; i < a.length; i++) {
input = sc.nextLine().split(" ");
int[] intinput = Arrays.asList(input).stream().mapToInt(Integer::parseInt).toArray();
a = intinput[0];
b = intinput[1];
}
}
答案 0 :(得分：1)
我认为您需要以这种方式更改2行：
a[i] = intinput[0];
b[i] = intinput[1];
答案 1 :(得分：0)
只需使用nextInt()扫描仪方法读取对，它就像分隔符一样使用所有空格符号（不仅仅是行尾）：
public class SumsInLoop {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the amount of sums you would like to calculate: ");
int n = sc.nextInt();
int a[] = new int[n];
int b[] = new int[n];
System.out.println("Please enter the values you would like to sum as pairs of two numbers: ");
for (int i = 0; i < a.length; i++) {
a[i] = sc.nextInt();
b[i] = sc.nextInt();
}
}
}
答案 2 :(得分：0)
你正在使用nextLine（）方法，这对字符串输入很有用，但它不是整数或其他原始数据的最佳解决方案。
此外，这行代码错误：
public class SumsInLoop {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the amount of sums you would like to calculate: ");
int n = sc.nextInt();
int a[] = new int[n];
int b[] = new int[n];
for (int i = 0; i < a.length; i++) {
System.out.println("Please enter the values you would like to sum as pairs of two numbers: ");
// Read pair and store it inside i-th position of a and b arrays
System.out.println("Enter first number: ");
a[i] = sc.nextInt();
System.out.println("Enter second number: ");
b[i] = sc.nextInt();
}
// Close scanner
sc.close();
// Prints every sum
for(int i = 0; i < a.length; i++){
System.out.println(i + "-th sum is: " + (a[i] + b[i]));
}
}
}
因为您将整数值存储为整数数组。 您必须将该值存储在[i]中，以便尊重变量类型。
我这样做：
a[i]在这里，您将使用nextInt（）读取每一对，这对于整数数据。
每次将项目存储在数组的第i个位置时，最后您可以将b[i]和Enter the amount of sums you would like to calculate:
4
Please enter the values you would like to sum as pairs of two numbers:
Enter first number:
2
Enter second number:
1
Please enter the values you would like to sum as pairs of two numbers:
Enter first number:
3
Enter second number:
4
Please enter the values you would like to sum as pairs of two numbers:
Enter first number:
5
Enter second number:
6
Please enter the values you would like to sum as pairs of two numbers:
Enter first number:
7
Enter second number:
8
0-th sum is: 3
1-th sum is: 7
2-th sum is: 11
3-th sum is: 15
相加。
结果示例：
class spawn(object):
def __init__(self,place1,place2):
self.place1=place1
self.place2=place2
def AIPrototype(self):#The important parts to this error star here
global x,y,x1,y1
pygame.draw.rect(screen,THECOLORS['blue'],(self.place1,self.place2,50,50))
x1=self.place1
y1=self.place2#end here
if x1<x:
xspeed1=1
slopex1=x-x1
if x1>x:
xspeed1=-1
slopex1=x1-x
if y1<y:
yspeed1=1
slopey1=y-y1
if y1>y:
yspeed1=-1
slopey1=y1-y
#
hypo1=((slopex1**2)+(slopey1**2))**0.5
speedmark1=hypo1/3
speedy1=slopey1/speedmark1
speedx1=slopex1/speedmark1
movex1=speedx1
movey1=speedy1
if x1<=640 and x1>=0:
if x1>x:
x1+=xspeed1*movex1
if x1<x:
xspeed1=0
if y1<=480 and x1>=0:
if y1>y:
y1+=yspeed1*movey1
if y1<y:
yspeed1=0
if x1<=640 and x1>=0:
if x1<x:
x1+=xspeed1*movex1
if x1>x:
xspeed1=0
if y1<=480 and x1>=0:
if y1<y:
y1+=yspeed1*movey1
if y1>y:
yspeed1=0
#
if x1>640:
x1=640
if x1<0:
x1=0
if y1>480:
y1=480
if y1<0:
y1=0
self.place1=x1#start
self.place2=y1#end