Question

我不知道为什么我一直收到错误＆＃34;字符串索引超出范围＆＃34;第47行print_data的另一个错误（数据。有人可以解释一下原因吗？谢谢

def open_file():
  user_input = input('Enter a file name: ')
  try:
    file = open(user_input, 'r')
    return file
  except FileNotFoundError:
    return open_file()


def read_data(file):
  counter = [0 for _ in range(9)]
  for line in file.readlines():
    num = line.strip()
    if num.isdigit():
      i = 0
      digit = int(num[i])
      while digit == 0 and i < len(num):
        i += 1
        digit = int(num[i])
      if digit != 0:
        counter[digit - 1] += 1
  return counter


def print_data(data):
  benford = [30.1, 17.6, 12.5, 9.7, 7.9, 6.7, 5.8, 4.1, 4.6]
  header_str = "{:5s} {:7s}{:8s}"
  data_str = "{:d}:{:6.1f}% ({:4.1f}%)"
  total_count = sum(data)
  print(header_str.format("Digit", "Percent", "Benford"))
  for index, count in enumerate(data):
    digit = index + 1
    percent = 100 * count / total_count
    print(data_str.format(digit, percent, benford[index]))


def main():
  file = open_file()
  data = read_data(file)
  print_data(data)
  file.close()

if __name__ == "__main__":
  main()

这是我给出的确切错误

Traceback (most recent call last):
  File "./lab08.py", line 52, in <module>
    main()
  File "./lab08.py", line 47, in main
    data = read_data(file)
  File "./lab08.py", line 26, in read_data
    digit = int(num[i])

Answer 1

我认为错误源于此：

while digit == 0 and i < len(num): i += 1 digit = int(num[i])

如果你交换后两行，你将正确索引，即：

while digit == 0 and i < len(num): digit = int(num[i]) i += 1

例如，如果您的字符串num的长度为10，则最后一个元素位于索引9（从0开始索引）。对于该循环的第一次迭代，您将具有数字num[1]，对于第十次迭代，您将具有num[10]。

另一种方法是使用这样的列表理解： for n in num: if digit != 0: break digit = int(n)

我的代码错误？字符串索引超出范围？

1 个答案: