Question

我有文件data.txt，下面的python代码读取文本和表单字典。

file：data.txt

10/20   vinay   
05/31   hunachyal
11/23   mine

bday_list = {}


infile = open("data.txt")
for line in infile:
    List_array = [w.strip() for w in line.split("\t")]
    bday_list[List_array[0]] = List_array[1]
#    print line

print bday_list


 Op: {'11/23': 'mine', '10/20': 'vinay', '05/31': 'hunachyal'}

同样如何以OP

中显示的格式获取下面文件的dictinaory

文件

  10/20 Name    vinay   phone   +91094xxx   
  05/31 Name    hunachyal   phone +91jndjxx
  11/23 Name    mine    phone +92jdddxxx

  OP:

  {'11/23': {'Phone': '+91kexxx', 'Name': 'mine'}, '10/20': {'Phone': '+919xxxx', 'Name': 'vinay'}, '05/31': {'Phone': '+9194xxxx', 'Name': 'hunachyal'}}

或者python中是否有任何方法可以形成数据库，我可以轻松获取数据。

Answer 1

尝试以下方法：

>>> data = """10/20 Name    vinay   phone   +91094xxx   
...   05/31 Name    hunachyal   phone +91jndjxx
...   11/23 Name    mine    phone +92jdddxxx
... """
>>> 
>>> result = {}
>>> 
>>> for line in data.splitlines():
...     dataList = line.split()
...     result[dataList[0]] = {dataList[1]: dataList[2], dataList[3]: dataList[4]}
... 
>>> result
{'11/23': {'Name': 'mine', 'phone': '+92jdddxxx'}, '10/20': {'Name': 'vinay', 'phone': '+91094xxx'}, '05/31': {'Name': 'hunachyal', 'phone': '+91jndjxx'}}

Answer 2

你也可以尝试这个

bday_list = {}
with open('data.txt', 'r') as R:
    for line in R:
        l = line.strip().split()  # split the line to list
        bday_list[l[0]] = {k:v for k,v in zip(l[1::2], l[2::2])}

PS，
如果您使用infile = open(...)而不是with open() as infile:来处理文件句柄，那么您应该记得close之后的文件句柄。

Answer 3

试试这个：）

infile = open("data.txt")
for line in infile:
    List_array = [w.strip() for w in line.split("\t")]
    bday_list[List_array[0]] ={"Phone":List_array[1],"Name":List_array[2]}

Answer 4

这应该适合你：

f = open('filename.txt').readlines()

f = [i.strip('\n').split() for i in f]

new_dict = {i[0]:{i[b]:i[b+1] for b in range(1, len(i), 2) if b+1 < len(i)} for i in f}

print new_dict

读取文本文件并在python中形成字典

4 个答案: