Question

脚本提示用户选择要执行的计算（调用）。在我选择一个选项并计算数字后，我得到随机结果。例如4 + 5 = 27和4 * 4 = 0。

@echo off
goto :main

:addition
    set /a FNUM1=%~1
    set /a FNUM2=%~2
    set /a RESULT=FNUM + FNUM2
    echo RESULT: %RESULT%
goto :eof

:subtraction
    set /a FNUM1=%~1
    set /a FNUM2=%~2
    set /a RESULT=FNUM - FNUM2
    echo RESULT: %RESULT%
goto :eof

:multiplication
    set /a FNUM1=%~1
    set /a FNUM2=%~2
    set /a RESULT=FNUM * FNUM2
    echo RESULT: %RESULT%
goto :eof

:division
    set /a FNUM1=%~1
    set /a FNUM2=%~2
    set /a RESULT=FNUM / FNUM2
    echo RESULT: %RESULT%
goto :eof

:main
    echo Welcome to the calculator
    echo Please chose one of the following options:
    echo    1 - Addition
    echo    2 - Subtraction
    echo    3 - Multiplication
    echo    4 - Division
    echo    5 - Quit

    set /p CHOICE=
    if "%CHOICE%"=="1" (
        echo YOU CHOSE ADDITION!
        echo Enter first number:
        set /p NUM1=
        echo Added by:
        set /p NUM2=
        call :addition %NUM1% %NUM2%
    )

    if "%CHOICE%"=="2" (
        echo YOU CHOSE SUBTRACTION!
        echo Enter first number:
        set /p NUM1=
        echo Subtracted by:
        set /p NUM2=
        call :subtraction %NUM1% %NUM2%
    )


    if "%CHOICE%"=="3" (
        echo YOU CHOSE MULTIPLICATION!
        echo Enter first number:
        set /p NUM1=
        echo Multiplied by:
        set /p NUM2=
        call :multiplication %NUM1% %NUM2%
    )

    if "%CHOICE%"=="4" (
        echo YOU CHOSE DIVISION!
        echo Enter first number:
        set /p NUM1=
        echo Divided by:
        set /p NUM2=
        call :division %NUM1% %NUM2%
    )

    if "%CHOICE%"=="5" (
        echo Good Bye!
    )
goto :eof

我尝试使用“/ a”来设置FNUM1和FNUM2，但我仍然得到随机结果。

感谢您的任何建议。

Answer 1

set FNUM1=4
set FNUM2=4

set /a RESULT=%FNUM1%*%FNUM2%
echo RESULT: %RESULT%

结果：16

set /a "RESULT = FNUM1 * FNUM2"
echo RESULT: %RESULT%

结果：16

Answer 2

:main
echo Welcome to the calculator
echo Please chose one of the following options:
echo    1 - Addition
echo    2 - Subtraction
echo    3 - Multiplication
echo    4 - Division
echo    5 - Quit

set "operation="
set "choice="
set /p CHOICE=
if "%CHOICE%"=="1" set "operation=ADDITION"
if "%CHOICE%"=="2" set "operation=SUBTRACTION"
if "%CHOICE%"=="3" set "operation=MULTIPLICATION"
if "%CHOICE%"=="4" set "operation=DIVISION"
if "%CHOICE%"=="5" (
    echo Good Bye!
)
if not defined operation echo illegal choice&goto main

echo YOU CHOSE %operation%!
echo Enter first number:
set /p NUM1=
echo Second number:
set /p NUM2=
call :%operation% %NUM1% %NUM2%
goto main
goto :eof

您的主要问题可以通过阅读有关delayed expansion的一些SO项目来解释。简而言之，在一个块（带括号的系列行）中，任何%var%在遇到块时被var的值替换，因此更改块内的num?不会改变传递给子例程的值 - 它是块{em>的执行开始时的num? 。

Mods：在执行choice之前将set/p设置为 nothing ，因为如果只按 Enter ，变量将不会变为空，但未更改

建立一个新变量operation并将其设置为 nothing

取决于所做出的选择（也许您应该从提示中尝试choice /?以获得更好的方法）将operation设置为适当的值。

由于每个条目产生（几乎）相同的文本，请输入值，然后执行计算。

也许你可能想要像

这样的东西

echo %1 ? %2=%result%

在每个子例程中，或者将子例程中的operation更改为+，-等，并在主例程中，在call :%operation%...之后（选择子例程）试试）

echo％num1 %% operation %% num2％=％result％

应填写operation按例程设置＆＃34;： oldvalueofoperation ＆＃34;

尝试在BATCH脚本中调用数学函数，但获取结果的随机数

2 个答案: