Question

我正在使用此代码从网址中删除查询参数，但它无效。你能好好看一下吗？

const url = require('url')

const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
delete obj.query.query2
const link = url.format(obj)
console.log(link) // I was expecting the removal of query2 but it didn't happen

它记录了与上面传递的相同的网址，为什么query2未删除？感谢

Answer 1

您需要从对象中删除搜索节点

const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
delete obj.query.query2
delete obj.search

const link = url.format(obj)
console.log(link)

这会返回您的网址https://github.com/Microsoft/VisualStudio2017Launch_KeynoteDemos/tree/master/VSTS%20and%20DevOps

Answer 2

即使您从查询对象中删除了query2，搜索字段中仍然存在query2。

const url = require('url');

const obj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)
console.log(obj);
delete obj.query.query2
delete obj.search
console.log(obj);
const link = url.format(obj)
console.log(link)

Answer 3

如果您查看url模块的源代码（https://github.com/defunctzombie/node-url/blob/master/url.js）。你可以看到它将首先查看搜索节点（第413行）。同时删除它，以便评估查询对象。

删除obj.search;

Answer 4

＆＃13;

const url = require("url")

const urlObj = url.parse('http://www.example.com/path?query1=val1&query2=val2', true)

delete urlObj.query.query2
delete urlObj.search

const newUrl = url.format(urlObj)

console.log(newUrl) // print >> http://www.example.com/path?query1=val1

＆＃13;

使用node.js删除查询参数不起作用

4 个答案: