如何在我的计算机上启用文件夹以允许php将文件移入其中?

时间:2017-05-29 02:23:51

标签: php mysql file-upload

所以,我正在尝试使用PHP将文件上传到文件夹中,但是,图像没有出现。没有错误消息。我认为会出现错误,告诉我他们无法上传。

<?php

if (isset($_POST['postsubmit'])) {

    $postTitle = trim($_POST['posttitle']);
    $postAuth = trim($_POST['postauthor']);
    $postStat = trim($_POST['poststatus']);
    $post_image = $_FILES['image']['name'];
    $post_image_temp = $_FILES['image']['tmp_name'];
    $postTags = trim($_POST['posttags']);
    $postDate = date('y-m-d');
    $postContent = trim($_POST['postcontent']);
    $postComCount = 4;

    move_uploaded_file($post_image_temp, "../images/$post_image");

}

?>

<h1>Add New Post</h1>

<div class="col-xs-6">
<form action="" method="POST" enctype="multipart/form-data">
    <div class="form-group">
        <label for="posttitle">Post Title</label>
        <input type="text" name="posttitle" id="posttitle" class="form-control" maxlength="99"/>
    </div>
    <div class="form-group">
        <label for="postauthor">Post Author</label>
        <input type="text" name="postauthor" id="postauthor" class="form-control" maxlength="25"/>
    </div>
    <div class="form-group">
        <label for="postauthor">Post Status</label>
        <input type="text" name="poststatus" id="poststatus" class="form-control" maxlength="25"/>
    </div>
    <div class="form-group">
        <label for="postauthor">Post Image</label>
        <input type="file" name="image" id="image" class="form-control"/>
    </div>
    <div class="form-group">
        <label for="postauthor">Post Tags</label>
        <input type="text" name="posttags" id="posttags" class="form-control" maxlength="25"/>
    </div>
    <div class="form-group">
        <label for="postcontent">Post Content</label>
        <textarea type="text" name="postcontent" id="postcontent" class="form-control" rows="15" maxlength="10000"></textarea>
    </div>
    <button class="btn btn-primary" value="submit" name="postsubmit">Submit Post</button>
</form>
</div>

2 个答案:

答案 0 :(得分:0)

向调试添加错误报告,如下所示:

    @model Trabalho.Models.Contact

@{
    ViewData["Title"] = "Details";
}

<h2>Details</h2>

    <h4>Contact</h4>

    <dl class="dl-horizontal">
        <dt>
            @Html.DisplayNameFor(model => model.ContactNumber)
        </dt>
        <dd>
            @Html.DisplayFor(model => model.ContactNumber)
        </dd>
        <dt>
            @Html.DisplayNameFor(model => model.Country)
        </dt>
        <dd>
            @Html.DisplayFor(model => model.Country)
        </dd>
        <dt>
            @Html.DisplayNameFor(model => model.Email)
        </dt>
        <dd>
            @Html.DisplayFor(model => model.Email)
        </dd>
        <dt>
            @Html.DisplayNameFor(model => model.Name)
        </dt>
        <dd>
            @Html.DisplayFor(model => model.Name)
        </dd>
    </dl>
<div>
    <a asp-action="Edit" asp-route-id="@Model.ContactId">Edit</a> |
    <a asp-action="Index">Back to List</a>
</div>

答案 1 :(得分:0)

尝试更改

parameter=list(minlen=2)

move_uploaded_file($post_image_temp, "../images/$post_image");

这是因为你只是传递一个字符串move_uploaded_file($post_image_temp, "../images/".$post_image); 而不是变量本身