Question

我正在努力想出一个正则表达式，找到包含在方括号中的任何字符串。我从维基百科中删除了一个包含许多段落的大量文档：

"Theology translates into English from the Greek theologia (θεολογία) which derived from Τheos (Θεός), meaning "God," and -logia (-λογία),**[12]** meaning "utterances, sayings, or oracles" (a word related to logos **[λόγος][Citation needed]**".

期望的结果是：

"Theology translates into English from the Greek theologia (θεολογία) which derived from Τheos (Θεός), meaning "God," and -logia (-λογία), meaning "utterances, sayings, or oracles" (a word related to logos".

任何建议都将不胜感激。谢谢！

Answer 1

文档中的**也是吗？你只提方括号。

如果是，那么正则表达式将是

(\*\*\[.*?\]\*\*)

如果它只是方括号，那么这与你之后的情况相符：

(\[.*?\])

你没有提到一种语言，但在Python中，这将由

完成

import re

my_re = r'(\*\*\[.*?\]\*\*)'
my_string = '"Theology translates into English from the Greek theologia (θεολογία) which derived from Τheos (Θεός), meaning "God," and -logia (-λογία),**[12]** meaning "utterances, sayings, or oracles" (a word related to logos **[λόγος][Citation needed]**".'
my_corrected_string = re.sub(my_re, '', my_string)

print(my_corrected_string)

正则表达式：查找包含在方括号中的任何字符串

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