Question

我在我的android代码中使用了Volley，HttpClient和HttpUrlConnection，它从传感器管理器获取传感器指标。我需要通过POST请求将这些指标导出到nodejs服务器。每当传感器值发生变化时，我都需要一个post请求异步到http服务器

MainActivity.java

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server.js

package com.example.rpothuraju.gyrometrics;

import android.app.Activity;
import android.hardware.Sensor;
import android.hardware.SensorEvent;
import android.hardware.SensorEventListener;
import android.hardware.SensorManager;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;

import com.android.volley.Request;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;

public class MainActivity extends Activity implements SensorEventListener{
TextView textView;
private SensorManager sensorManager;
//private Sensor sensor;

@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    textView = (TextView) findViewById(R.id.metrics);

    sensorManager = (SensorManager) getSystemService(SENSOR_SERVICE);
    //sensor = sensorManager.getDefaultSensor(Sensor.TYPE_GYROSCOPE);


}

protected void onResume()
{
    super.onResume();
    sensorManager.registerListener(this, sensorManager.getDefaultSensor(Sensor.TYPE_MAGNETIC_FIELD),SensorManager.SENSOR_DELAY_FASTEST);
}

protected void onStop()
{
    sensorManager.unregisterListener(this);
    super.onStop();
}

public void onAccuracyChanged(Sensor arg0, int arg1)
{
    //Do nothing.
}

public void onSensorChanged(SensorEvent event)
{
    if (event.accuracy == SensorManager.SENSOR_STATUS_UNRELIABLE)
    {
        return;
    }

    String url ="http://localhost:8080/?X=" + event.values[0] + "&&Y= " + event.values[1] + "&&Z=" + event.values[2];

    StringRequest stringRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.i("VOLLEY", response);
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e("VOLLEY", error.toString());
        }
    });

    textView.setText("Orientation X (Roll) :"+ Float.toString(event.values[0]) +"\n"+
            "Orientation Y (Pitch) :"+ Float.toString(event.values[1]) +"\n"+
            "Orientation Z (Yaw) :"+ Float.toString(event.values[2]));

}
}

我无法看到服务器的任何响应...... ??

Answer 1

您创建请求对象但从不将其发送到服务器。
您应该为它设置一个请求队列。

RequestQueue queue;
//inside the oncreate method 
queue = Volley.newRequestQueue(mCtx.getApplicationContext());
//and for sending request
String url ="http://localhost:8080/?X=" + event.values[0] + "&&Y= " + event.values[1] + "&&Z=" + event.values[2];

    StringRequest stringRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Log.i("VOLLEY", response);
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e("VOLLEY", error.toString());
        }
    });
<br>
queue.add(stringRequest);

为了更好地接近（为网络请求创建单一类），请查看以下链接，
https://developer.android.com/training/volley/requestqueue.html

Answer 2

在您的网址中，尝试使用http://10.0.2.2/代替http://localhost

这可以在模拟器中使用。

android post请求使用volley

2 个答案: