当我尝试从我的php应用程序向我的控制器发送POST请求时,我遇到了问题。
这是我从php(客户端)的请求:
$.ajax({
url: "http://myURL:8080/myApplication/myMethod",
contentType: "application/json; charset=UTF-8",
crossDomain: true,
dataType: "json",
method: "post",
data: data,
success: function (data) {
/*things to do */
}
});
我在html上包含档案:
<!DOCTYPE html>
<html>
<body onload="start()">
<head lang="pt-br">
<meta charset="utf-8">
<script type="text/javascript" src="https://www.google.com/jsapi">
</script>
<link rel="stylesheet"
href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"> </script>
<script src="./jquery/jquery.ajax-cross-origin.min.js"></script>
...
ajaxRequestMethod above
</end tags>
</html>
这是在服务器端,在我的控制器上的java:
@CrossOrigin(origins = "*", maxAge = 3600)
@RequestMapping(value = "/myMehtod", method = RequestMethod.POST)
public @ResponseBody List<Alimento> calculo(@RequestBody PlanoAlimentarWrapper wrapper) {
PlanoAlimentarWrapper melhorPlano = new PlanoAlimentarWrapper();
HashMap<Alimento, Integer> alimentos = new HashMap<>();
wrapper.createBestPlan(melhorPlano, wrapper.getPlano(), alimentos);
List<Alimento> retornoMelhorPlano = new ArrayList<Alimento>();
retornoMelhorPlano.addAll(melhorPlano.getPlano());
return retornoMelhorPlano;
}
当我尝试请求此方法时,我收到以下错误:
Object {readyState=0, status=0, statusText="error", ...}
它可能是什么?