我正在使用FireBase实现一个应用程序,在这个应用程序中我必须通过用户输入唯一ID来保存用户信息。我怎样才能做到这一点。实际上它使用随机生成的值保存数据。但我想添加一个用户输入唯一ID。
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_home);
txtDetails = (TextView) findViewById(R.id.txt_user);
inputName = (EditText) findViewById(R.id.name);
inputEmail = (EditText) findViewById(R.id.email);
btnSave = (Button) findViewById(R.id.btn_save);
mFirebaseInstance = FirebaseDatabase.getInstance();
// get reference to 'users' node
mFirebaseDatabase = mFirebaseInstance.getReference("users");
// store app title to 'app_title' node
mFirebaseInstance.getReference("app_title").setValue("Realtime Database");
// app_title change listener
mFirebaseInstance.getReference("app_title").addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
Log.e(TAG, "App title updated");
// update toolbar title
}
@Override
public void onCancelled(DatabaseError error) {
// Failed to read value
Log.e(TAG, "Failed to read app title value.", error.toException());
}
});
// Save / update the user
btnSave.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String name = inputName.getText().toString();
String email = inputEmail.getText().toString();
// Check for already existed userId
if (TextUtils.isEmpty(userId)) {
createUser(name, email);
} else {
createUser(name, email);
}
}
});
toggleButton();
}
// Changing button text
private void toggleButton() {
if (TextUtils.isEmpty(userId)) {
btnSave.setText("Save");
} else {
btnSave.setText("Save");
}
}
/**
* Creating new user node under 'users'
*/
private void createUser(String name, String email) {
// TODO
// In real apps this userId should be fetched
// by implementing firebase auth
if (TextUtils.isEmpty(userId)) {
userId = mFirebaseDatabase.push().getKey();
}
User user = new User(name, email);
mFirebaseDatabase.child(userId).push().setValue(user);
addUserChangeListener();
}
/**
* User data change listener
*/
private void addUserChangeListener() {
// User data change listener
mFirebaseDatabase.child(userId).addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
User user = dataSnapshot.getValue(User.class);
// Check for null
if (user == null) {
Log.e(TAG, "User data is null!");
return;
}
Log.e(TAG, "User data is changed!" + user.name + ", " + user.email);
// Display newly updated name and email
// txtDetails.setText(user.name + ", " + user.email);
// clear edit text
inputEmail.setText("");
inputName.setText("");
toggleButton();
}
@Override
public void onCancelled(DatabaseError error) {
// Failed to read value
Log.e(TAG, "Failed to read user", error.toException());
}
});
}
private void updateUser(String name, String email) {
// updating the user via child nodes
if (!TextUtils.isEmpty(name))
mFirebaseDatabase.child(userId).child("name").setValue(name);
if (!TextUtils.isEmpty(email))
mFirebaseDatabase.child(userId).child("email").setValue(email);
}
答案 0 :(得分:0)
要以唯一标识符保存用户数据,我建议您使用email address
代替of pushing a new key
或使用uid
。电子邮件地址独特且易于使用。但由于Firebase不接受密钥中的.
符号,我建议您对电子邮件地址进行编码,如下所示:
name@email.com - >名@电子邮件,玉米
如您所见,我已使用逗号.
更改了点符号,
。为了实现这一点,我使用这种方法重新启动你:
static String encodeUserEmail(String userEmail) {
return userEmail.replace(".", ",");
}
static String decodeUserEmail(String userEmail) {
return userEmail.replace(",", ".");
}
希望它有所帮助。