构建您的CustomConstraintValidator

Question

我创建了自定义约束验证器：

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div style="margin-left: 23px;">
  <legend class="legend">List of Stores which completed the survey so far</legend>

  <select for="postage" id="store_select">
          <option value="">Please select...</option>
          <option value="finished" id ="Finshed">Stores Completed.</option>
          <option value="notFinished" id ="NotFinsh">Stores Not Completed</option>
  </select>
  <br />
  <br />
  <div id="completedStores" class="displaystore2">
    Stores Completed Div
  </div>
  <br />

  <div id="notCompletedStores" class="displaystore1">
    NOT Stores Completed Div
    <br />
    <br />
  </div>
</div>

在docs中声明：

返回当前验证的对象。

，但对我来说，它会返回<?php $cn= mysqli_connect('localhost','testuser','password','invoicedb'); // Check connection if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } echo "string"; if($_SERVER["REQUEST_METHOD"] == "POST") {echo "string"; $fname=$_POST['F_Name']; $lname=$_POST['L_Name']; $emailID=$_POST['EmailID']; $phone_number=$_POST['Phone_Number']; $reference_code=$_POST[‘R_Code’]; $branch=$_POST[‘subject’]; $percentage=$_POST[‘percentage’]; echo "insert into students(first_name,last_name,email,phone_number,reference_code,branch,percentage) VALUES ('$fname','$lname','$emailID','$phone_number','$reference_code','$branch','$percentage')"; mysqli_query($cn,"insert into students(first_name,last_name,email,phone_number,reference_code,branch,percentage) VALUES ('$fname','$lname','$emailID','$phone_number','$reference_code','$branch','$percentage')"); //best outside the if statement so user isn't stuck on a white blank page. header("location:confirm.php"); exit; } ?>。

P.S。我不想将此约束分配给实体，仅限于某些表单或字段。

我的表单属性已经过验证：

class CustomConstraint extends Constraint
{
    public $message = '';
}

class CustomConstraintValidator extends ConstraintValidator
{
    public function validate($value, Constraint $constraint)
    {
         exit($this->context->getObject()); // returns null
    }
}

实体中的财产：

NULL

更新

我尝试将约束放在其他字符串属性上，我仍然得到->add('rejectReasons', null, array( 'property' => 'name', 'multiple' => true, 'constraints' => array( new CustomConstraint(array( 'message' => 'Application can not be refused.' )), ) ));。

Answer 1

看看ExecutionContextInterface它说：

getObject（）返回当前验证的对象。

如果验证器当前正在验证类约束，则   返回该类的对象。如果它是验证属性或   getter constraint ，属性/ getter所属的对象是   返回。

在其他情况下，返回null。

正如您所看到的，您必须分配给某个类或属性或getter。否则你会得到null。

Answer 2

如果您开发类约束验证器，请记住添加getTargets方法作为示例：

public function getTargets()
{
    return self::CLASS_CONSTRAINT;
}

如文档

中所述here

Answer 3

对于那些使用依赖项本身进行表单验证的人可能会有所帮助。我假设Symfony版本是3.4或4.1，并且您的项目中有df.pivot_table(index=['ticker'], columns=['other'], values=['cov'], fill_value=1).values array([[ 1.00000000e+00, 5.62318492e-05, 6.05076457e-05, 6.99435817e-05, 4.20812754e-05], [ 5.62318492e-05, 1.00000000e+00, 8.57872875e-05, 1.16723972e-04, 4.63723078e-05], [ 6.05076457e-05, 8.57872875e-05, 1.00000000e+00, 8.88688235e-05, 4.29291322e-05], [ 6.99435817e-05, 1.16723972e-04, 8.88688235e-05, 1.00000000e+00, 5.04454626e-05], [ 4.20812754e-05, 4.63723078e-05, 4.29291322e-05, 5.04454626e-05, 1.00000000e+00]])。

构建您的CustomConstraintValidator

处理带有某种依赖性的Symfony表单验证程序的最佳方法是使用CustomValidators

上面是我用来与他们合作的示例。

假设我们有一个类似的实体

symfony/form

我们不需要填充// src/Entity/myEntity.php namespace App\Entity; ... class myEntity { private $id; private $name; // string, required private $canDrive; // bool, not required (default=false) private $driveLicense; // string, not required (default = null) public function __construct() { $this->canDrive = false; } // getters and setters }（因为该属性不是必需的），但是如果$driveLicense从$canDrive更改为false，则现在{{1} } 必须具有一个值。

true与$driveLicense相关。

要为此构建一个表单并在FormType上正确验证$driveLicense（最佳实践），我们需要构建一个CustomConstraintValidator。

构建CanDriveValidator

$canDrive

翻译器文件-可选

$driveLicense

验证者

// src/Validator/Constraints/CanDrive.php
namespace App\Validator\Constraints;

use Symfony\Component\Validator\Constraint;

class CanDrive extends Constraint
{
    public $message = 'invalid_candrive_args'; // I like translators :D
}

表单myEntityType

//src/translators/validators.en.yaml // 
invalid_candrive_args: When "{{ candrivelabel }} " field is checked you must fill "{{ drivelicenselabel }}"

现在，当使用myEntityType表单的调用// src/Validator/Constraints/CanDriveValidator.php namespace App\Validator\Constraints; use Symfony\Component\Validator\Constraint; use Symfony\Component\Validator\ConstraintValidator; class CanDriveValidator extends ConstraintValidator { /** * Checks if the passed value is valid. * * @param mixed $value The value that should be validated * @param Constraint $constraint The constraint for the validation */ public function validate($value, Constraint $constraint) { $canDriveField = $this->context->getObject(); // the Field using this validator $form = $canDriveField->getParent(); // the formType where the Field reside $myEntity = $form->getData(); // The Entity mapped by formType if ($myEntity->getCanDrive() == true && $myEntity->getDriveLicense() == null) { $this->context->buildViolation($constraint->message) ->setParameter('{{ candrivelabel }}', 'Can Drive') ->setParameter('{{ drivelicenselabel }}', 'Drive License') ->addViolation(); } } }方法并且检查 canDrive 字段并且 driveLicense 为空白时，将对canDrive字段引发违反。如果 canDrive 设置为false（未选中，未提交），则不会发生任何事情，即使 driveLicense 为空白，表单也将有效。

Answer 4

答案很简单。写：

this->context->getRoot()->getData()

你有对象。

Symfony - 在字段约束类中获取实体对象

4 个答案:

构建您的CustomConstraintValidator

构建CanDriveValidator