Question

我有以下存储过程，但在导入Visual Studio 2015的实体框架时，没有列。我在程序声明之前和之后尝试过SET FMTONLY OFF，但仍然没有运气。

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET FMTONLY OFF
GO
ALTER PROCEDURE [dbo].[up_Search] (
    @name VARCHAR(255) = NULL,
    @position VARCHAR(10) = NULL,
    @altposition VARCHAR(10) = NULL,
    @notice VARCHAR(10) = NULL,
    @lengthofservice VARCHAR(10) = NULL,
    @source VARCHAR(10) = NULL,
    @educationLevel VARCHAR(10) = NULL,
    @email VARCHAR(10) = NULL,
    @CVRead CHAR = NULL,
    @SARef CHAR = NULL,
    @Collections CHAR = NULL,
    @Sales CHAR = NULL,
    @TeamLead CHAR = NULL,
    @Training CHAR = NULL,
    @HR CHAR = NULL,
    @Business CHAR = NULL,
    @UK CHAR = NULL,
    @fromDate varchar(20) = NULL,
    @toDate varchar(20) = NULL,
    @ExperienceID_1 varchar(50) = null,
    @ExperienceID_2 varchar(50) = null,
    @Language_1 varchar(20) = NULL
)
AS
SET NOCOUNT ON
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED

DECLARE @sql varchar(max)
DECLARE @i int
DECLARE @firstname VARCHAR(255), @lastname VARCHAR(255)


PRINT @educationLevel

SET @name = LTRIM(@name)

SET @i = CHARINDEX(' ', @name)


if @i > 1 
begin
    set @firstname = LEFT(@name, @i-1)
    set @lastname = RIGHT(@name, LEN(@name)-@i)
end 

SET @sql = 'SELECT c.[CandidateID] as [Unique ID]   ,[DateOfApplication] as [Date Of Application], 
        ISNULL ( RecruiterDisplayName , ''---'') as [Recruiter] 
    ,p.[Description] as [Position]   ,t.Description as [Title]   ,[FirstName] as [First Name]   ,[LastName] as [Last Name]   
    ,[IDNumber] as [ID Number]   ,[Mobile] as [Mobile]   ,[Email]  as [Email]   ,s.[Description] as [From Advert],
    c.[LengthOfServicePersonal] as [LengthOfService]

    FROM Candidate c  
    LEFT JOIN Position p ON c.PositionID = p.PositionID  
    LEFT JOIN SourceAdvert s ON c.SourceAdvertID = s.SourceAdvertID  
    LEFT JOIN Titles t ON c.TitleID = t.TitleID  
    LEFT JOIN Lookup_Experience le ON le.CandidateID = c.CandidateID        
    LEFT JOIN Experience ex ON ex.[ExperienceID] = le.[ExperienceID]
    LEFT JOIN Languages ln ON ln.[LanguageID] = c.[Language]    
    WHERE (c.Status =0) '   -- only show candidates with not set status

if @firstname is not null
    set @sql = @sql + ' AND (FirstName LIKE ''%' + @firstname + '%'' AND LastName LIKE ''%' + @lastname + '%'' OR IDNumber LIKE ''%' + @name + '%'')'
else begin  
    set @sql = @sql + ' AND (FirstName LIKE ''%' + @name + '%'' OR LastName LIKE ''%' + @name + '%'' OR IDNumber LIKE ''%' + @name + '%'')'
end
if @notice is not null
    set @sql = @sql + ' AND (NoticePeriod <= ' + @notice + ')'
if @position is not null AND @altposition is not null
        set @sql = @sql + ' AND (c.PositionID = ' + @position + ' OR c.AlternatePositionID = ' + @altposition + ')'
    else
        if @position is not null and @altposition is null
            set @sql = @sql + ' AND c.PositionID = ' + @position 
        else 
            if @position is null and @altposition is not null
                set @sql = @sql + ' AND c.AlternatePositionID = ' + @altposition 
if @lengthofservice is not null
    set @sql = @sql + ' AND (LengthOfService_1 >= ' + @lengthofservice + 
        ' OR LengthOfService_2 >= ' + @lengthofservice + 
        ' OR LengthOfService_3 >= ' + @lengthofservice + 
        ' OR LengthOfService_4 >= ' + @lengthofservice + 
    ')'
if @source is not null
    set @sql = @sql + ' AND (s.[SourceAdvertID] = ' + @source + ')'
if @educationLevel is not null
    set @sql = @sql + ' AND (EducationLevel >= ' + @educationLevel  + ')'
if @email is not null and @email <> ''
    set @sql = @sql + ' AND (Email like  ''%'+  @email +  '%'')'
if @CVRead is not null
    set @sql = @sql + ' AND (CVRead = ' + CAST(@CVRead AS CHAR(1)) + ')'
if @SARef is not null
    set @sql = @sql + ' AND (SARef = ' + CAST(@SARef AS CHAR(1)) + ')'  
if @Collections is not null
    set @sql = @sql + ' AND (Collections = ' + CAST(@Collections AS CHAR(1)) + ')'
if @Sales is not null
    set @sql = @sql + ' AND (Sales = ' + CAST(@Sales AS CHAR(1)) + ')'
if @TeamLead is not null
    set @sql = @sql + ' AND (TeamLead = ' + CAST(@TeamLead AS CHAR(1)) + ')'
if @Training is not null
    set @sql = @sql + ' AND (Training = ' + CAST(@Training AS CHAR(1)) + ')'
if @HR is not null
    set @sql = @sql + ' AND (HR = ' + CAST(@HR AS CHAR(1)) + ')'
if @Business is not null
    set @sql = @sql + ' AND (Business = ' + CAST(@Business AS CHAR(1)) + ')'
if @UK is not null
    set @sql = @sql + ' AND UK = ' + CAST(@UK AS CHAR(1)) 
if @fromDate is not null
    set @sql = @sql + ' AND [DateOfApplication] >= ''' + @fromDate + ''''
if @toDate is not null
    set @sql = @sql + ' AND [DateOfApplication] <= ''' + @toDate + ''''
if @ExperienceID_1 is not null AND @ExperienceID_2 is null
    set @sql = @sql + ' AND ex.description = ''' + @ExperienceID_1 + ''''
if @ExperienceID_2 is not null
    set @sql = @sql + ' AND (ex.description = ''' + @ExperienceID_1 + ''' OR ex.description = ''' + @ExperienceID_2 + ''')'
if @Language_1 is not null
    set @sql = @sql + ' AND ln.Description = ''' + @Language_1 + ''''



set @sql = @sql + ' ORDER BY [LastTouched] DESC, [Date Of Application] DESC';


PRINT @sql

EXECUTE (@sql)

Answer 1

我已经解决了我的问题。我所做的是创建一个具有相同名称和参数的存储过程，但只有一个简单的选择查询将返回列 - 我已经从PRINT @sql复制了查询结果。然后我用该过程更新实体框架，该过程有列。保存Visual Studio中的所有更改后，我使用旧的存储过程更改过程，一切正常100％

导入到Visual Studio 2015时，存储过程不返回任何列

1 个答案: