php电报answersercallbackquery sendmessage

时间:2017-05-23 18:57:53

标签: php telegram telegram-bot php-telegram-bot

我试图在PHP中开发Telegram Bot,但是当我按下内联按钮时,我无法让我的机器人回答用户。 有人帮我在调用answerCallback方法后发送消息(sendMessage方法)吗?

这是我的最后一个试用代码:

if ($call_back_query != null) {

    $response = $call_back_query;
    $botUrl = "https://api.telegram.org/bot" . BOT_TOKEN . "/answerCallbackQuery";
    $postFields = array('callback_query_id' =>  $call_back_id, 'text' => $response);
    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type:multipart/form-data"));
    curl_setopt($ch, CURLOPT_URL, $botUrl); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, $postFields);
    $output = curl_exec($ch);

        //send Text
    $response = "help me if you can, i'm feeling down";
    header("Content-Type: application/json");
    $parameters = array('chat_id' => $chatId, "text" => $response);
    $parameters["method"] = "sendMessage";
    echo json_encode($parameters);


  }

谢谢

1 个答案:

答案 0 :(得分:0)

好的,我已经理解了这个问题:

在sendText中,我必须使用$call_back_from而不是$chatId,因为他回答了回调查询,而不是简单的消息(我想是这样......)

$chatId = isset($message['chat']['id']) ? $message['chat']['id'] : "";

$call_back_from = isset ($update['callback_query']['from']['id']) ? $update['callback_query']['from']['id'] : "";

代码将是

if ($call_back_query != null) {

    $response = $call_back_query;
    $botUrl = "https://api.telegram.org/bot" . BOT_TOKEN . "/answerCallbackQuery";
    $postFields = array('callback_query_id' =>  $call_back_id, 'text' => $response);
    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_HTTPHEADER, array("Content-Type:multipart/form-data"));
    curl_setopt($ch, CURLOPT_URL, $botUrl); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, $postFields);
    $output = curl_exec($ch);

        //send Text
    $response = "help me if you can, i'm feeling down";
    header("Content-Type: application/json");
    $parameters = array('chat_id' => $call_back_from, "text" => $response);
    $parameters["method"] = "sendMessage";
    echo json_encode($parameters);


  }

希望这可能会有所帮助! 试一试!