Hibernate Envers复合ID实体无法解析

时间:2017-05-22 21:23:20

标签: hibernate hibernate-envers

我有一个复合ID表,在我的数据库中有一个附加字段,以及使用EmbeddedId java持久性注释配置的相应实体模型。在我的应用程序中执行编辑时,一切正常。但是,当尝试使用Hibernate Envers检索审计数据时,代码失败,给我以下堆栈跟踪:

Caused by: org.hibernate.QueryException: could not resolve property: contract_id of: com.mycompany.model.DesignContract_AUD
    at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:62)
    at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:56)
    at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1801)
    at org.hibernate.hql.internal.ast.tree.FromElementType.getPropertyType(FromElementType.java:393)
    at org.hibernate.hql.internal.ast.tree.FromElement.getPropertyType(FromElement.java:507)
    at org.hibernate.hql.internal.ast.tree.DotNode.getDataType(DotNode.java:660)
    at org.hibernate.hql.internal.ast.tree.DotNode.prepareLhs(DotNode.java:264)
    at org.hibernate.hql.internal.ast.tree.DotNode.resolve(DotNode.java:204)
    at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:109)
    at org.hibernate.hql.internal.ast.tree.FromReferenceNode.resolve(FromReferenceNode.java:104)
    at org.hibernate.hql.internal.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:1013)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1286)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.exprOrSubquery(HqlSqlBaseWalker.java:4699)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.comparisonExpr(HqlSqlBaseWalker.java:4169)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2134)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2059)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2059)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.whereClause(HqlSqlBaseWalker.java:813)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:607)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:311)
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:259)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:262)
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:190)

那里有两个主要问题。首先,Contract_Id不是字段。我将JoinColumn配置为" FK_CONTRACT"的正确名称。其次,我不明白为什么它试图使用java类名作为审计表,而不是使用@Table注释中设置的名称,即" CONTRACT_DESIGNS"。我的课程如下:

@Entity
@DynamicInsert
@DynamicUpdate
@SelectBeforeUpdate
@Table(name="CONTRACTS")
@Audited
public class Contract implements Serializable {
    private static final long serialVersionUID = 1L;

    private List<DesignContract> designs;
    @OneToMany(mappedBy = "pk.contract", fetch = FetchType.EAGER, cascade = {CascadeType.ALL}, orphanRemoval=true)
    @Fetch(value = FetchMode.SUBSELECT)
    public List<DesignContract> getDesigns() {
        return designs;
    }
    public void setDesigns(List<DesignContract> designs) {
        this.designs= designs;
    }
}


@Entity
@AssociationOverrides({
        @AssociationOverride(name = "pk.contract",
                joinColumns = @JoinColumn(name = "FK_CONTRACT")),
        @AssociationOverride(name = "pk.design",
                joinColumns = @JoinColumn(name = "FK_DESIGN")) })
@Table(name="CONTRACT_DESIGNS")
@Audited
public class DesignContract implements Serializable {
    private static final long serialVersionUID = 1L;

    public DesignContract () {

    }
    public DesignContract (Contract contract, Design design) {
        pk.setContract(contract);
        pk.setDesign(design);
    }

    private DesignContractId pk = new DesignContractId();
    @EmbeddedId
    public DesignContractId getPk() {
        return pk;
    }
    public void setPk(DesignContractId pk) {
        this.pk = pk;
    }

    @Transient
    public Contract getContract() {
        return getPk().getContract();
    }
    public void setContract(Contract contract) {
        getPk().setContract(contract);
    }

    @Transient
    public Design getDesign() {
        return getPk().getDesign();
    }
    public void setDesign(Design design) {
        getPk().setDesign(design);
    }

    private Double goal;
    @Column(name = "GOAL", nullable = true, insertable = true, updatable = true, precision = 5, scale = 2)
    @Basic
    public Double getGoal() {
        return this.goal;
    }
    public void setGoal(Double goal) {
        this.goal = goal;
    }
}

@Embeddable
public class DesignContractId implements Serializable {
    private static final long serialVersionUID = 1L;

    private Contract contract;
    private Design design;

    @ManyToOne
    public Contract getContract() {
        return contract;
    }
    public void setContract(Contract contract) {
        this.contract = contract;
    }

    @ManyToOne
    public Design getDesign() {
        return design;
    }
    public void setDesign(Design design) {
        this.design = design;
    }
}

为所有三个模型实现了toString(),hashCode()和equals()方法,为简洁起见,我省略了它们。

我检索审计信息的测试代码是非常基本的,因为我主要只是做一些事情正在发挥作用的概念证明,并且可以初始化附加到我的主契约实体的延迟初始化记录。当我调用DesignContract列表的size()方法时会发生错误,根据我发现的其他帖子强制Hibernate Enver的ListProxy的使用方法。

    AuditReader reader = AuditReaderFactory.get(sessionFactory.openSession());
    List<Number> revisionsContract = reader.getRevisions(Contract.class, contractId);
    for (Number revisionNum : revisionsContract) {
        System.out.println("    revisionNum = " + revisionNum);
        Contract contract = reader.find(Contract.class, contractId, revisionNum);
        System.out.println(contract.getDesigns().size());
        System.out.println(contract.getDesigns());
        System.out.println(contract);
    }

出于调试目的,我将show_sql设置为true,并且在调用size()时Hibernate正在尝试的查询没有意义:

select e__ from com.mycompany.model.DesignContract_AUD e__ where e__.contract_id = :contract_id and e__.originalId.REVISION_NUMBER.id = (select max(e2__.originalId.REVISION_NUMBER.id) from com.mycompany.model.DesignContract_AUD e2__ where e2__.originalId.REVISION_NUMBER.id <= :revision and e__.originalId.design = e2__.originalId.design and e__.originalId.contract = e2__.originalId.contract) and REVISION_TYPE != :delrevisiontype

同样,没有contract_id字段,因此我不知道在DesignContract和DesignContractId的模型中给出我的注释会得到什么,并且使用com.mycompany.model.DesignContract_AUD是我根本无法理解的东西。我甚至添加了@AuditTable注释,将其指向CONTRACT_DESIGNS_AUD表,但这并没有改变任何东西。在我的应用程序中执行正常操作(如编辑和保存合同)时,审计信息会正确添加到CONTRACT_DESIGNS_AUD表中,我可以通过直接sql直接查询信息。我不知道为什么会在AuditReader中发生这种情况。我的应用程序中有多个复合ID实体,它们都以相同的方式配置,它们都遇到相同的错误,带有未知的contract_id参数,以及查询中用于审计表的java类名。我确实尝试将我的模型配置为使用@IdClass注释而不是@EmbeddedId,但这只能帮助解析查询中的表名 - 它仍然试图根据contract_id进行过滤,当然,它无法解析。< / p>

我正在使用Hibernate 5.2.10.FINAL,我在阅读了复合ID实体后无法使用早期版本的Hibernate Envers时升级到了https://hibernate.atlassian.net/browse/HHH-7625

对于我做错的任何帮助都将不胜感激。

1 个答案:

答案 0 :(得分:1)

您遇到明确错误的问题。我们似乎在HHH-7625中实施了对@IdClass映射的支持时,我们没有正确地考虑@EmbeddedId

我已就此问题记录了JIRA问题HHH-11770,该问题已得到修复,并将包含在5.2.11.Final版本中。