我无法在QuickBlox中获得用户在线/离线状态。我尝试过使用 QBRoster 。
我为了吸引用户而编写的功能。
private void subscribeUserForStatus(ArrayList<Integer> mQBUserList) {
if (QBChatService.getInstance().getRoster() != null) {
mQbRoster = QBChatService.getInstance().getRoster(
QBRoster.SubscriptionMode.mutual, this);
mQbRoster.addRosterListener(this);
for (Integer mId : mQBUserList) {
try {
if (mQbRoster.contains(mId)) {
mQbRoster.subscribe(mId);
} else {
mQbRoster.createEntry(mId, null);
}
} catch (SmackException.NotConnectedException e) {
e.printStackTrace();
Log.e("Crash on subscription", e.getMessage());
}
}
}
}
答案 0 :(得分:4)
@mixin dummy(
$a: true,
$b: false,
$c: auto
) {
// do stuff
}
$params: (
a: false,
xyz: 'foo'
);
@include dummy($params...);
这也可以帮到你:
int userID = 45;
QBPresence presence = chatRoster.getPresence(userID);
if (presence == null) {
// No user in your roster
return;
}
if (presence.getType() == QBPresence.Type.online) {
// User is online
}else{
// User is offline
}
此链接很有帮助: https://quickblox.com/developers/Android_XMPP_Chat_Sample
答案 1 :(得分:2)
以上答案是正确的,您可以像这样使用
QBRosterListener rosterListener = new QBRosterListener() {
@Override
public void entriesDeleted(Collection<Integer> userIds) {
}
@Override
public void entriesAdded(Collection<Integer> userIds) {
}
@Override
public void entriesUpdated(Collection<Integer> userIds) {
}
@Override
public void presenceChanged(QBPresence presence) {
if (presence == null) {
// No user in your roster
return;
}
if (presence.getType() == QBPresence.Type.online) {
// User is online
}else{
// User is offline
}
}
};
答案 2 :(得分:0)
您可以使用此代码
Roster roster = xmppConnection.getRoster();
Collection<RosterEntry> entries = roster.getEntries();
Presence presence;
for(RosterEntry entry : entries) {
presence = roster.getPresence(entry.getUser());
System.out.println(entry.getUser());
System.out.println(presence.getType().name());
System.out.println(presence.getStatus());
}