Question

我有一个在Firefox中运行良好的XPath表达式，但是当我在IE中查看该文件时出现错误。是否有办法让IE了解我的表达？

我的XSL（我删除了很多，所以它更容易看到）。

<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:date="http://exslt.org/dates-and-times" exclude-result-prefixes="#all" >
	<xsl:output indent="yes"/>
	<xsl:output method="html" encoding="UTF-8"/>
	<xsl:template match="/">
		<html>
			<head>
				<title>
					<xsl:value-of select="versions/project" />
				</title>
				<style type="text/css">
					...
				</style>
			</head>
			<body>
				<div class="content">
					
								<xsl:for-each select="/releasenotes/notes/note[component/@type=$unitTag]">
									<xsl:for-each select=".[component/@number=$versionNumber and text/@type='new']">
										<li type="disc">
											<xsl:value-of select="text" />
											<xsl:for-each select="component[not(@type=$unitTag)]">
												<xsl:sort select="@type" order="ascending"/>
												, <a href="#{@type}_{@number}">
													<xsl:variable name="unitType" select="@type"/>
													<xsl:value-of select="//components/component[tag=$unitType]/name" />&#160;(<xsl:value-of select="@number" />)
												</a>
											</xsl:for-each>
										</li>
									</xsl:for-each>
								</xsl:for-each>
							
						</xsl:for-each>
					</xsl:for-each>
					
				</div>
			</body>
		</html>
	</xsl:template>
</xsl:stylesheet>

问题似乎在于这一行：

<xsl:for-each select=".[component/@number=$versionNumber and text/@type='new']">

导致此错误：

Expected token 'EOF' found '['. .-->[<--component/@number='$versionNumber' and text/@type='new']

Answer 1

对于变通方法，尝试使用等效的，未缩写的表达式.替换该特定self::node()，以使XSL跨浏览器工作。有关XPath中缩写步骤（.和..）之后谓词的相关最新问题：Selenium WebDriver Xpath current element attribute reports invalid Xpath exception

Answer 2

而不是

<xsl:for-each select="/releasenotes/notes/note[component/@type=$unitTag][component/@number=$versionNumber and text/@type='new']">

似乎你只是想要

<xsl:for-each select="/releasenotes/notes/note[component/@type=$unitTag and component/@number=$versionNumber and text/@type='new']">

或

Vue.component('vimeo', {
    template: '<iframe src="https://player.vimeo.com/video/' + this.videoId + '" width="640" height="360" frameborder="0" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>',
    props: ['videoId']
});

Vue.component('videos', {
    template: '<div id="videos">' + 
                '<div v-for="videoId in videoIds">' +
                    '<vimeo :video-id="videoId"></vimeo>' +
                '</div>' +
              '</div>',
    computed: {
        videoIds: function() {
            return store.state.videoIds;
        }
    }
});

Answer 3

XPath 1.0语法不允许

.[condition]，所以IE拒绝它是正确的。

您实际上可以替换

<xsl:for-each select=".[condition]">

与

<xsl:if test="condition">

或按照Martin Honnen的建议将其合并到父xsl:for-each中。

xsl文件中的XPath表达式在IE中不起作用

3 个答案: