Question

我有不同日期的日期列表：

data = as.POSIXct(c("2017-01-03 06:14:08","2017-01-03 06:15:08","2017-01-03 06:33:07","2017-01-03 06:57:57",
                    "2017-01-03 07:01:08","2017-01-03 07:15:08","2017-01-03 07:33:08","2017-01-03 08:29:08","2017-01-03 08:34:08"),tz = "GMT")

我想创建一个列，将日期分为1小时桶，从第30分钟开始，结果将在＆＃34; BUCKET＆＃34;下面的栏目

as.data.frame(data)
                 data   BUCKET
1 2017-01-03 06:14:08   530
2 2017-01-03 06:15:08   530
3 2017-01-03 06:33:07   630
4 2017-01-03 06:57:57   630
5 2017-01-03 07:01:08   630 
6 2017-01-04 07:15:08   630 
7 2017-01-04 07:33:08   730
8 2017-01-05 08:29:08   730
9 2017-01-05 08:34:08   830

Answer 1

这是一种方法......

bucket <- paste0(as.numeric(format(data-60*30,format("%H"))),"30")

bucket
[1] "530" "530" "630" "630" "630" "630" "730" "730" "830"

如何使用切割将日期分成1小时的垃圾箱

1 个答案: