当我尝试使用多个实体映射一个实体时，我收到此错误。
///这是我的候选人资料实体/////////
package com.demo.project.premiumjobportal.model;
import java.io.Serializable;
import java.util.List;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.validation.constraints.NotNull;
import javax.xml.bind.annotation.XmlRootElement;
import com.fasterxml.jackson.annotation.JsonBackReference;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
//Candidate details table : Master Table
@Entity
@Table(name="candidate_profile")
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
@XmlRootElement
public class CandidateProfile implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private int id;
@NotNull
@Column(name="first_name", length = 25)
private String firstName;
@NotNull
@Column(name="last_name", length = 25)
private String lastName;
@NotNull
@Column(name="username", length = 50)
private String username;
@Column(name="alt_email_id", length = 50)
private String alternateEmailId;
@NotNull
@Column(name="mobile_no", length = 15)
private String mobileNum;
@Column(name="alt_mobile_no", length = 15)
private String alternateMobileNum;
@Column(name="ssc_board", length = 50)
private String sscBoard;
@Column(name="ssc_school", length = 50)
private String sscSchool;
@Column(name="ssc_percent", length = 4)
private float sscPercentage;
@Column(name="ssc_year_of_passout", length = 4)
private int sscYearOfPassout;
@Column(name="hsc_board", length = 50)
private String hscBoard;
@Column(name="hsc_school", length = 50)
private String hscSchool;
@Column(name="hsc_percent", length = 4)
private float hscPercentage;
@Column(name="hsc_year_of_passout", length = 4)
private int hscYearOfPassout;
@Column(name="grad_university", length = 100)
private String gradiduteUniversity;
@Column(name="grad_institute", length = 100)
private String gradiduteInstitute;
@Column(name="grad_percent", length = 4)
private float gradidutePercentage;
@Column(name="grad_year_of_passout", length = 4)
private int gradiduteYearOfPassout;
@Column(name="postgrad_university", length = 100)
private String postGradiduteUniversity;
@Column(name="postgrad_institute", length = 100)
private String postGradiduteInstitute;
@Column(name="postgrad_percent", length = 4)
private float postGradidutePercentage;
@Column(name="postgrad_year_of_passout", length = 4)
private int postGradiduteYearOfPassout;
private String notes;
private String Password;
@OneToMany(mappedBy = "candidateProfile", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List experienceDetails;
@OneToMany(mappedBy = "candidateProfile", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List candidateJobs;
@ManyToOne
private Role roleName;
/* Constructor */
public CandidateProfile() {
super();
}
// Getters and Setters
///这是我的经验详情实体////////////
package com.cfa.project.premiumjobportal.model;
import java.io.Serializable;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.ManyToOne;
import javax.persistence.Table;
import javax.xml.bind.annotation.XmlRootElement;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
//Experience class, which connected with CandidateProfile.class
@Entity
@Table(name="experience_details")
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
@XmlRootElement
public class ExperienceDetails implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private int id;
@Column(name = "tot_experenice", length = 2)
private String totExperience;
@Column(name = "companies_month_experience")
private String companiesMonthExperience;
@Column(name = "skills")
private String _skills;
@Column(name = "extra_curricular")
private String extraCurricular;
private String notes;
/* Mapping : Joining with Candidate table */
@ManyToOne
private CandidateProfile candidateProfile;
/*Constructor*/
public ExperienceDetails() {
super();
}
/*Constructor using fields*/
/**
* @param id
* @param totExperience
* @param companiesMonthExperience
* @param _skills
* @param extraCurricular
* @param notes
* @param candidateProfile
*/
public ExperienceDetails(int id, String totExperience, String companiesMonthExperience, String _skills,
String extraCurricular, String notes, CandidateProfile candidateProfile) {
super();
this.id = id;
this.totExperience = totExperience;
this.companiesMonthExperience = companiesMonthExperience;
this._skills = _skills;
this.extraCurricular = extraCurricular;
this.notes = notes;
this.candidateProfile = candidateProfile;
}
/* Generating Getters and setters */
///这是我的角色实体//////
import java.io.Serializable;
import java.util.List;
import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;
import javax.persistence.OneToMany;
import javax.persistence.Table;
import javax.xml.bind.annotation.XmlRootElement;
import com.fasterxml.jackson.annotation.JsonBackReference;
import com.fasterxml.jackson.annotation.JsonIgnoreProperties;
@Entity
@Table(name="role")
@JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
@XmlRootElement
public class Role implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
private int id;
@Column(length = 10)
private String name;
@OneToMany(mappedBy = "roleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List candidateProfiles;
@OneToMany(mappedBy = "companyRoleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List recruiterDetails;
我得到的这个错误---------------- 无法为类型[[simple type，class com.demo.project.premiumjobportal.model.CandidateProfile]]评估Jackson反序列化：com.fasterxml.jackson.databind.JsonMappingException：名称为'defaultReference'的多个反向引用属性
无法评估类型[[simple type，class com.demo.project.premiumjobportal.model.CandidateProfile]]的Jackson反序列化：com.fasterxml.jackson.databind.JsonMappingException：Multiple back-名为'defaultReference'的引用属性
请帮我解决这个问题。我到处搜索，我尝试了所有解决方案但是我也遇到了这个错误。
答案 0 :(得分：4)
如果在项目中的getter / setter方法上使用@JsonBackReference两次以上，则应使用特定的引用名称区分它们。
在Role实体类中，您已使用@JsonBackReference两次
@OneToMany(mappedBy = "roleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List candidateProfiles;
@OneToMany(mappedBy = "companyRoleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference
private List recruiterDetails;
您应该将其更改为 -
@OneToMany(mappedBy = "roleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference(value="candidate-profiles")
private List candidateProfiles;
@OneToMany(mappedBy = "companyRoleName", fetch = FetchType.LAZY,cascade = CascadeType.REMOVE)
@JsonBackReference(value="recruiter-details")
private List recruiterDetails;