Question

我是Python和编程的新手，我正在尝试制作＆＃34;猜数字＆＃34;游戏。我使它工作但我希望添加选项以使用制动语句关闭游戏。我已经尝试了2天，但我想我卡住了。

这是有效的代码（没有关闭游戏的选项）：

import random
attempts = 0
secretNumber = random.randint(1,100)
while True:
    print("Guess a number between 1 and 100")
    guess=input()
    guess = int(guess)
    attempts = attempts + 1
    if guess >100 or guess<=0:
        attempts = attempts - 1
        print("Not allowed.Only numbers between 1 and 100 allowed! \n")
    elif guess < secretNumber and guess >0:
        print("Nope!Try a higher number! \n")
    elif guess > secretNumber and guess <100:
        print("Nope!Try a lower number \n")
    if guess == secretNumber:
        break

if guess == secretNumber:
            attempts = str(attempts)
print("Congratulations you found it after " + attempts + " attempts")

代码（带有关闭游戏的选项）不起作用：

import random
attempts = 0
secretNumber = random.randint(1,100)
while True:
    print("Guess a number between 1 and 100. You can exit game anytime by typing quit ")
    stop=input()
    stop=str(stop)
    if stop == "quit":
        break
        print("You quitted the game")
    else:
            continue
    guess=input()
    guess = int(guess)
    attempts = attempts + 1
    if guess >100 or guess<=0:
        attempts = attempts - 1
        print("Not allowed.Only numbers between 1 and 100 allowed! \n")
    elif guess < secretNumber and guess >0:
        print("Nope!Try a higher number! \n")
    elif guess > secretNumber and guess <100:
        print("Nope!Try a lower number \n")
    if guess == secretNumber:
        break

if guess == secretNumber:
            attempts = str(attempts)
print("Congratulations you found it after " + attempts + " attempts")

对不起这篇长篇文章，对于我做错了什么的任何帮助，甚至是使用 break 语句并且不使用def函数实现此目的的不同方法将不胜感激。非常感谢。

Answer 1

在Nick A和timgeb的评论中提到的，你可以适应一些事情。正如我在以下脚本中建议的那样，您可能需要查看try and except。请在脚本中找到评论。

import random
attempts = 0
secretNumber = random.randint(1,100)
# you can prompt the user within input()
stop=input("Guess a number between 1 and 100. You can exit game anytime by typing quit ")

while True:
    if stop == "quit": # as the the output of input() is a string, you can compare it with a string without str()
        print("You quitted the game")
        break
    try: # work with try and except to avoid problems whenever the user writes something else than 'quit' or an integer
        guess = int(stop)
        attempts += 1
        if guess >100 or guess<=0:
            attempts = attempts - 1
            print("Not allowed.Only numbers between 1 and 100 allowed! \n")
        elif guess < secretNumber and guess >0:
            print("Nope!Try a higher number! \n")
        elif guess > secretNumber and guess <=100: # note that it's <=. Otherwise nothing happens when the users chose 100
            print("Nope!Try a lower number \n")
    except: # if it's not possible to turn 'stop' into an integer we'd like to perform the following
        stop = input("No valid input, please guess again ") # Don't stop the script, let the user guess again
        continue # don't stop, but leave the current iteration (don't execute the rest) and start again at the beginning of the loop 
    if guess == secretNumber:
        attempts = str(attempts)
        print("Congratulations you found it after " + attempts + " attempts")
        break
    stop = input("Guess again ") # prompt for a new number every round of the loop

猜猜python中的数字。关闭游戏的选项

1 个答案: