Question

我写了一个程序，给出了家庭成员的类型。例如：0-3岁 - 宝宝，3-12岁儿童，12-31岁，年轻人等。为此，我使用if

Scanner keybord = new Scanner(System.in);
int age = klavye.nextInt();
age = klavye.nextInt(); 
age = klavye.nextInt();

int count = 0, count1 = 0, count2 = 0, count3 = 0, count4 = 0;

System.out.println("Enter the age of the family member : ");

if (age >= 0 && age <= 3);
    count++;

if(age >=4 && age <= 12);
    count1++;

if (age >= 13 && age <= 30);
    count2++;

if (age >= 31 && age <= 49);
    count3++;

if (age >=50 && age <= 120);
    count4++;

System.out.println(count+" "+ count3); // this to try to work "count"

当我写3次“49”时，我想显示count3 = 3，但只显示1。

Answer 1

您需要一个循环并将变量的初始化移到循环之外。

int count = 0, count1 = 0, count2 = 0, count3 = 0, count4 = 0;
do {
    ...
} while(...);

Answer 2

我稍微修改了你的代码：

Adedd循环多次输入。我已经在循环中训练了3个。
使用if..else if构造，而不是if。此更改不是强制性的，而是最佳做法。
从if语句中删除;

Scanner keybord = new Scanner(System.in);

int count = 0, count1 = 0, count2 = 0, count3 = 0, count4 = 0;

for (int i = 0; i < 3; i++) {
System.out.println("Enter the age of the family member : ");
int age = klavye.nextInt();

if (age >= 0 && age <= 3)
    count++;
else if(age >=4 && age <= 12)
  count1++;
else if (age >= 13 && age <= 30)
  count2++;
else if (age >= 31 && age <= 49)
  count3++;
else if (age >=50 && age <= 120)
  count4++;
}
System.out.println(count+" "+ count3);

Java练习 - 家庭成员

2 个答案: