Question

clc
%clear all
close all
G=1000;
R=0.372;
Rs=0.2;
lamda=300*10^(-9);
I=0.01;
h=6.626*10^(-34);
c=3*10^8;
mun=100;
taun=5*10^(-9);
mup=25;
taup=5*10^(-9);
e=8.854*10^(-12);
alpha=0.473;
We=50*10^(-9);
Wa=5*10^(-9);
ni=1;
%VD=-10:0.01:10;
q=1.602*10^(-19);
n=1.5;
k=1.38*10^(-23);
T=283;
Na=1*10^(14);
VT=((k*T)/q);    %VT=KT/q
G= ((1-R)*(lamda*I))/(h*c);%G=(1-R)?I/hc
syms x
fn=int(1/(mun*taun*((q*Na*(x-Wa))/e)));
syms x
FN=int(exp(-(alpha+fn)),(We+Wa),(We+x)); 
Jn=q*G*alpha*exp(fn)*FN;
x=-10:0.01:10;
JN=subs(Jn);
syms x
fp=int(1/(mup*taup*((q*Na*(x-Wa))/e))); 
syms x
FP=int(exp(-(alpha+fp)),(We+x),We);
Jp=q*G*alpha*exp(fp)*FP;
x=-10:0.01:10; 
JP=subs(Jp);
Jph=JN+JP;
J0=((q*ni*Wa)/(2*sqrt(taun*taup)));
J=zeros(1,2003);
j=1;
J(1,1)=0;
for VL=0:0.001:5
    Jpart=J0*(exp(VL-(J(j,1)*Rs)/(n*VT)))-1;
    J(j+1)=-Jph+Jpart; 
    VL1(j+1)=VL; 
    j=j+1;
    plot(VL1(j),J(j,1), 'r')
    hold on
    grid on   
end

在这段代码中我收到错误：

在作业A（:) = B中，A和B中的元素数必须相同。

Code2中的错误（第49行） Ĵ（J + 1）= - JPH + Jpart;

我想获得如下图所示的输出：

Output

没有输出。请有人帮帮我......

Answer 1

检查你的模型是你的功课，并且充满了各种错误。但仅仅是代码，现在正在发挥作用：

<?php
ini_set('display_errors', 1);
$string="Hello world";
echo strReplace($string,"llo","zz");
echo strReplace($string,"o","xx");
function strReplace($string,$toReplace,$replacement)
{
    while($indexArray=checkSubStringIndexes($toReplace,$string))
    {
        $stringArray=  getChars($string);
        $replaced=false;
        $newString="";
        foreach($stringArray as $key => $value)
        {
            if(!$replaced && in_array($key,$indexArray))
            {
                $newString=$newString.$replacement;
                $replaced=true;
            }
            elseif(!in_array($key,$indexArray))
            {
                $newString=$newString.$value;
            }
        }
        $string=$newString;
    }
    return $string;
}
function getLength($string)
{
    $counter=0;
    while(true)
    {
        if(isset($string[$counter]))
        {
            $counter++;
        }
        else 
        {
            break;
        }
    }
    return $counter;
}
function getChars($string)
{
    $result=array();
    $counter=0;
    while(true)
    {
        if(isset($string[$counter]))
        {
            $result[]=$string[$counter];
            $counter++;
        }
        else 
        {
            break;
        }
    }
    return $result;
}
function checkSubStringIndexes($toReplace,$string)
{
    $counter=0;
    $indexArray=array();
    $newCounter=0;
    $length=  getLength($string);
    $toReplacelength=  getLength($toReplace);
    $mainCharacters= getChars($string);
    $toReplaceCharacters= getChars($toReplace);
    for($x=0;$x<$length;$x++)
    {
        if($mainCharacters[$x]==$toReplaceCharacters[0])
        {
            for($y=0;$y<$toReplacelength;$y++)
            {
                if(isset($mainCharacters[$x+$y]) && $mainCharacters[$x+$y]==$toReplaceCharacters[$y])
                {
                    $indexArray[]=$x+$y;
                    $newCounter++;
                }
            }
            if($newCounter==$toReplacelength)
            {
                return $indexArray;
            }
        }
    }
}

为什么A和B中的元素对于我的代码必须相同？

1 个答案: