我可以将这个if语句转换为Python中的函数吗？

Question

我将重复此代码，因此我尝试将其转换为函数。 但我不断收到错误。 的修改 不，我收到错误：缺少1个位置参数：'连接' 在方法中放置“连接”的最佳方法是什么？

def sqlfirst(self, connection):
    firstname = str(self.first_entry.get())
    lastname = str(self.last_entry.get())     
    license = str(self.lic_entry.get())
    if (firstname and not lastname and not license):  # "You entered first name."
        try:
            connection = pypyodbc.connect('Driver={SQL Server};Server=;Database=;Trusted_Connection=yes;')
        except pypyodbc.Error as ex:
            sqlstate = ex.args[0]
            if sqlstate == '28000':
                self.answer_label['text'] = "You do not have access." 
        cursor = connection.cursor() 
        SQLCommand = ("SELECT LASTNAME, FIRSTNAME, L_LICNUMBER "      
            "FROM dbo. "   # table name
            "with (nolock)"
            "WHERE FIRSTNAME = ?")
        Values = [firstname]
        cursor.execute(SQLCommand,Values)
        return cursor.fetchmany(10)




def calculate2(self):
    results = self.sqlfirst()
    if results:

        self.output1.delete(0, END)
        self.output1.insert(0,results[2])
        connection.close()
        traceback.print_exc()

以下是我的旧代码：

我可以将上面的内容变成一个名为的函数，这样我可以随时调用sqlfirst（self）吗？我试过了：

def sqlfirst(self):
    firstname = str(self.first_entry.get())
    lastname = str(self.last_entry.get())     
    if (firstname and not lastname):  # "You entered first name."
        try:
            connection = pypyodbc.connect('Driver={SQL Server};Server=;Database=;Trusted_Connection=yes;')
        except pypyodbc.Error as ex:
            sqlstate = ex.args[0]
            if sqlstate == '28000':
                self.answer_label['text'] = "You do not have access." 
        cursor = connection.cursor() 
        SQLCommand = ("SELECT LASTNAME "      
            "FROM dbo.NAME "   # table name
            "with (nolock)"
            "WHERE FIRSTNAME = ?")
        Values = [firstname]
        cursor.execute(SQLCommand,Values)
        results = cursor.fetchmany(10)



def calculate(self):
    self.sqlfirst()
        if results:

            self.output2.delete(0, END)
            self.output2.insert(0,results[2])
            connection.close()