Region Growing python

Question

我在python中研究区域增长算法的实现。但是当我在输出上运行此代码时，我得到的黑色图像没有错误。在输入图像和种子值上使用CV阈值函数我使用鼠标单击在元组中存储x，y值。

def get8n(x, y, shape):
    out = []
    if y-1 > 0 and x-1 > 0:
        out.append( (y-1, x-1) )
    if y-1 > 0 :
        out.append( (y-1, x))
    if y-1 > 0 and x+1 < shape[1]:
        out.append( (y-1, x+1))
    if x-1 > 0:
        out.append( (y, x-1))
    if x+1 < shape[1]:
        out.append( (y, x+1))
    if y+1 < shape[0] and x-1 > 0:
        out.append( ( y+1, x-1))
    if y+1 < shape[0] :
        out.append( (y+1, x))
    if y+1 < shape[0] and x+1 < shape[1]:
       out.append( (y+1, x+1))
    return out

def region_growing(img, seed):
    list = []
    outimg = np.zeros_like(img)

    list.append((seed[0], seed[1]))
    while(len(list)):
        pix = list[0]
        outimg[pix[0], pix[1]] = 255
        for coord in get8n(pix[0], pix[1], img.shape):
            if img[coord[0], coord[1]] > 0:
                outimg[coord[0], coord[1]] = 255
                list.append((coord[0], coord[1]))
        list.pop(0)
    return outimg

def on_mouse(event, x, y, flags, params): 
    if event == cv2.EVENT_LBUTTONDOWN: 
        print 'Seed: ' + str(x) + ', ' + str(y) 
        clicks.append((y,x)) 

clicks = []
image = cv2.imread('lena.jpg', 0) 
ret, img = cv2.threshold(image, 200, 255, cv2.THRESH_BINARY) 
cv2.namedWindow('Input') 
cv2.setMouseCallback('Input', on_mouse, 0, ) 
cv2.imshow('Input', img) 
cv2.waitKey() 
seed = clicks[-1] 
cv2.imshow('Region Growing', region_growing(img, seed)) 
cv2.waitKey() 
cv2.destroyAllWindows()

Answer 1

我的get8n（）函数遇到了一些问题所以我重写了它。我相信下面的代码可以满足您的要求。 region_growing（）函数中有两行被注释掉。如果取消注释它们，它们将显示处理过程中发生的动画。这是一种可视化代码并让您了解事情失败的好方法。

此外，在您的代码中，您可以将已经处理过的像素添加到“待处理”列表中。这导致无限循环。我添加了一个检查，以防止已处理的像素被添加回列表。

import cv2
import numpy as np

def get8n(x, y, shape):
    out = []
    maxx = shape[1]-1
    maxy = shape[0]-1

    #top left
    outx = min(max(x-1,0),maxx)
    outy = min(max(y-1,0),maxy)
    out.append((outx,outy))

    #top center
    outx = x
    outy = min(max(y-1,0),maxy)
    out.append((outx,outy))

    #top right
    outx = min(max(x+1,0),maxx)
    outy = min(max(y-1,0),maxy)
    out.append((outx,outy))

    #left
    outx = min(max(x-1,0),maxx)
    outy = y
    out.append((outx,outy))

    #right
    outx = min(max(x+1,0),maxx)
    outy = y
    out.append((outx,outy))

    #bottom left
    outx = min(max(x-1,0),maxx)
    outy = min(max(y+1,0),maxy)
    out.append((outx,outy))

    #bottom center
    outx = x
    outy = min(max(y+1,0),maxy)
    out.append((outx,outy))

    #bottom right
    outx = min(max(x+1,0),maxx)
    outy = min(max(y+1,0),maxy)
    out.append((outx,outy))

    return out

def region_growing(img, seed):
    list = []
    outimg = np.zeros_like(img)
    list.append((seed[0], seed[1]))
    processed = []
    while(len(list) > 0):
        pix = list[0]
        outimg[pix[0], pix[1]] = 255
        for coord in get8n(pix[0], pix[1], img.shape):
            if img[coord[0], coord[1]] != 0:
                outimg[coord[0], coord[1]] = 255
                if not coord in processed:
                    list.append(coord)
                processed.append(coord)
        list.pop(0)
        #cv2.imshow("progress",outimg)
        #cv2.waitKey(1)
    return outimg

def on_mouse(event, x, y, flags, params):
    if event == cv2.EVENT_LBUTTONDOWN:
        print 'Seed: ' + str(x) + ', ' + str(y), img[y,x]
        clicks.append((y,x))

clicks = []
image = cv2.imread('lena.bmp', 0)
ret, img = cv2.threshold(image, 128, 255, cv2.THRESH_BINARY)
cv2.namedWindow('Input')
cv2.setMouseCallback('Input', on_mouse, 0, )
cv2.imshow('Input', img)
cv2.waitKey()
seed = clicks[-1]
out = region_growing(img, seed)
cv2.imshow('Region Growing', out)
cv2.waitKey()
cv2.destroyAllWindows()

点击她的帽子左侧时的结果如下：

Answer 2

上面提出的解决方案在概念上是正确的，但从数字的角度来看，它们包含一些严重的问题，使它们的像素数排序为 N^2。如果您可以将信息存储在提供随机访问的数组中，则无需在列表中搜索像素，也可以对连通性函数进行 cythonized。此外，如果能够提供您自己的相似度函数，那就太好了。

所以这是我对在 Jupyter 笔记本中运行的改进的、绝对更快的版本的建议：

导入的第一个单元格：

import numpy as np
import cv2

%pylab inline 

%load_ext Cython

第二个单元格（不要合并第一个）：

%%cython
# Use %%cython -a for more verbose output, note %%cython should be on the first line in the cell!
def get_8_connected(int x, int y, shape):
    cdef int xmax = shape[0]-1
    cdef int ymax = shape[1]-1
    cdef int connected_pixel_x 
    cdef int connected_pixel_y
    cdef int dx, dy
    
    connected_pixels = list()
    
    for dx in range(3):
        for dy in range(3):
            connected_pixel_x  = x + dx - 1
            connected_pixel_y = y + dy - 1
            if connected_pixel_x < 0 or connected_pixel_x > xmax or \
                connected_pixel_y < 0 or connected_pixel_y > ymax or \
                (connected_pixel_x == x and connected_pixel_y == y):
                    pass
            else: 
                connected_pixels.append((connected_pixel_x,connected_pixel_y)) 
    return  connected_pixels

区域合并的第三个单元格

def region_growing(img, 
                   seed_points, 
                   test = lambda seed_x, seed_y, x, y, img, outimg : img[x,y] != 0,
                   colormap=None):
    
    processed = np.full((img.shape[0],img.shape[1]), False)
    
    if colormap is None:
        outimg = np.zeros_like(img)
    else:
        outimg = np.zeros((img.shape[0],img.shape[1],colormap.shape[1]),dtype=np.uint8)
    
    for index, pix in enumerate(seed_points):
        processed[pix[0], pix[1]] = True
        if colormap is None:
            outimg[pix[0], pix[1]] = img[pix[0], pix[1]]
        else:
            outimg[pix[0], pix[1]]  = colormap[index % len(colormap)]
    
    while(len(seed_points) > 0):
        pix = seed_points[0]
            
        for coord in get_8_connected(pix[0], pix[1], img.shape):
            if not processed[coord[0],coord[1]]:
                test_result = test(pix[0], pix[1], coord[0], coord[1], img, outimg)
                if test_result:
                    outimg[coord[0], coord[1]]  = outimg[pix[0], pix[1]]
                    if not processed[coord[0],coord[1]]:
                        seed_points.append(coord)
                    processed[coord[0],coord[1]] = True
                    
        seed_points.pop(0)
    return outimg

并且可以使用与以前相同的逻辑从另一个单元格调用它：

def on_mouse(event, x, y, flags, params):
    if event == cv2.EVENT_LBUTTONDOWN:
        print( 'Seed: ' + str(x) + ', ' + str(y), img[y,x])
        clicks.append((int(y), int(x)))
        
clicks = []
image = cv2.imread('lena.bmp', 0)
ret, img = cv2.threshold(image, 128, 255, cv2.THRESH_BINARY)
cv2.namedWindow('Input')
cv2.setMouseCallback('Input', on_mouse, 0, )
cv2.imshow('Input', img)
cv2.waitKey()
cv2.destroyAllWindows()

seed = clicks
out = region_growing(img, seed)
cv2.imshow('Region Growing', out)
cv2.waitKey()
cv2.destroyAllWindows()

有一些小的功能差异。输出中的区域要么由种子处的原始图像的值标记，要么由可选颜色图中的值标记。颜色图需要指定给定 als 无符号 8 位整数的 RGB 颜色。也可以传入一个定制的测试函数，替换：

test = lambda seed_x, seed_y, x, y, img, outimg : img[x,y] != 0

例如：

test = lambda seed_x, seed_y, x, y, img, outimg : abs(img[x,y] - img[seed_x, seed_y]) < 4

将产生所有连接到原始种子且强度步长低于 4 的像素。

在我的上下文中，它适用于单色和彩色图像。这既适用于 2d 数组，也适用于 3D 数组。

如果 Cython 无法使用，函数 get_8_connected 可以替换为：

def get_8_connected(x, y, shape):
    xmax = shape[0]-1
    ymax = shape[1]-1
    
    connected_pixels = list()
    
    for dx in range(3):
        for dy in range(3):
            connected_pixel_x  = x + dx - 1
            connected_pixel_y = y + dy - 1
            if connected_pixel_x < 0 or connected_pixel_x > xmax or \
                connected_pixel_y < 0 or connected_pixel_y > ymax or \
                (connected_pixel_x == x and connected_pixel_y == y):
                    pass
            else:
                connected_pixels.append((connected_pixel_x,connected_pixel_y))
    return  connected_pixels```

Answer 3

针对python 3.x的添加（），例如：print（“ Some something”）