Question

请允许我在前言中说我确实已经包括（也适用于字符串，endl，而且字面上一切都不起作用）;就语法而言，我的IDE没有显示任何错误;我无法理解为什么会出现这个问题？它在我写的其他一些C ++代码示例中工作正常。

所以我想做一个小游戏，公牛和奶牛。我的主要代码如下：

#include <iostream>

#include "stdafx.h"
#include "BullsAndCows.h"



using std::cout;
using std::endl;
using std::cin;
using std::string;

int main()
{

    string userInput = "";
    bool playAgain = false;

    int gameDiff;

    constexpr char * GREETING = "Welcome to Bulls and Cows! Please enter the difficulty level: (1) Easy, (2) Medium, (3) Hard";

    cin >> gameDiff;

    do
    {
        BullsAndCows *bc = new BullsAndCows();
        bc->playGame(gameDiff);

    } while (playAgain);


    constexpr char * INFORMATION = "Total Word Length  is: ";

    //Introduce the game.

    cout << GREETING <<endl;

    return 0;
}

我的标题：

#ifndef BULLSANDCOWS_H
#define BULLSANDCOWS_H



class BullsAndCows {

public:


    void playGame(int gameDiff);


};

#endif

最后，我的BullsAndCows.cpp文件：

#include <iostream>
#include <string>
#include "stdafx.h"
#include "BullsAndCows.h"

using std::cout;
using std::endl;
using std::cin;
using std::string;

void BullsAndCows::playGame(int gameDiff) {

    string wordGuess = "";
    string secretWord = "";
    int numBulls = 0;
    int numCows = 0;
    int numGuesses = 0;

    switch (gameDiff)
    {

    case 1: {
        numGuesses = 30;

        secretWord = "Hello";

        for (int i = 0; i < 30; i++) {

            numBulls = 0;
            numCows = 0;

            cout << "Word Length to Guess Is Five, you have " << numGuesses << " guesses remaining" << endl;
            cout << "Enter your word guess";
            cin >> wordGuess;

            for (int j = 0; j < wordGuess.length; j++) {
                if (wordGuess.at(j) == secretWord.at(j)) {
                    numBulls++;
                }
                else if (secretWord.find(wordGuess.at(j)) != -1) {
                    numCows++;
                }
            }

            cout << "Bulls: " << numBulls << endl;
            cout << "Cows: " << numCows << endl;

            if (numBulls == secretWord.length) {
                cout << "YOU WIN!" << endl;
                break;
            }

        }

        break;
    }
        case 2:
            numGuesses = 20;
            break;
        case 3:
            numGuesses = 10;
            break;
    }

}

我得到的错误“cout不是std的成员”，cout符号不能用于using声明。在此之前我使用“使用命名空间std”并且会返回错误，例如“BullsAndCows”不是命名空间或类（如果它不是类，那么我必须是火星人）。还有一些关于失踪的“;”在userInput之前，例如在我的main.cpp代码中;没有任何意义，因为没有任何东西可以忽略。我正在使用VS2017。为什么C ++会成为一种讨厌的语言？

Answer 1

放置指令

#include "stdafx.h"

在任何其他include指令之前。

Cout不是std的成员，也不是c ++的其他问题

1 个答案: