问题: 我正在尝试为每个 ID 组中的所有行创建等于1的变量 x2 ,其中 time x1 从1切换到0。 此外,在切换后,运行中每连续0, x2 设置为1.
我试图弄清楚如何使用library(dplyr)
执行此操作,但无法弄清楚如何查看组中的先前记录。
输入数据:
ID<-c("1","1","1","1","1","2","2","2","2","3","3","3","4","4","5","5","5")
time<-c("1","2","3","4","5","1","2","3","4","1","2","3","1","2","1","2","3")
x1<-c("0","1","1","1","1","0","0","0","0","1","0","0","1","1","1","0","1")
df<-data.frame(ID,time,x1)
必填项:
ID time x1 x2
1 1 0 0
1 2 1 0
1 3 1 0
1 4 1 0
1 5 1 0
2 1 0 0
2 2 0 0
2 3 0 0
2 4 0 0
3 1 1 0
3 2 0 1
3 3 0 1
4 1 1 0
4 2 1 0
5 1 1 0
5 2 0 1
5 3 1 0
答案 0 :(得分:1)
最好是拥有&#39; x1&#39;作为numeric
列
library(data.table)
setDT(df)[, x2 := (cumsum(x1) < 2)*cumsum(c(FALSE, diff(x1) < 0)), ID]
df
# ID time x1 x2
# 1: 1 1 0 0
# 2: 1 2 1 0
# 3: 1 3 1 0
# 4: 1 4 1 0
# 5: 1 5 1 0
# 6: 2 1 0 0
# 7: 2 2 0 0
# 8: 2 3 0 0
# 9: 2 4 0 0
#10: 3 1 1 0
#11: 3 2 0 1
#12: 3 3 0 1
#13: 4 1 1 0
#14: 4 2 1 0
#15: 5 1 1 0
#16: 5 2 0 1
#17: 5 3 1 0
ID<-c("1","1","1","1","1","2","2","2","2","3","3","3","4","4","5","5","5")
time<-c("1","2","3","4","5","1","2","3","4","1","2","3","1","2","1","2","3")
x1<- as.integer(c("0","1","1","1","1","0","0","0","0","1","0","0","1","1","1","0","1"))
df<-data.frame(ID,time,x1)
答案 1 :(得分:0)
如果您想要dplyr
答案,可以在按ID分组后在mutate
中使用@ akrun代码
library(dplyr)
ID<-c("1","1","1","1","1","2","2","2","2","3","3","3","4","4","5","5","5")
time<-c("1","2","3","4","5","1","2","3","4","1","2","3","1","2","1","2","3")
x1<- as.integer(c("0","1","1","1","1","0","0","0","0","1","0","0","1","1","1","0","1"))
df<-data.frame(ID,time,x1)
df <- df %>%
group_by(ID) %>%
mutate(x2 = (cumsum(x1) < 2)*cumsum(c(FALSE, diff(x1) < 0)))
df
# ID time x1 x2
# 1 1 0 0
# 1 2 1 0
# 1 3 1 0
# 1 4 1 0
# 1 5 1 0
# 2 1 0 0
# 2 2 0 0
# 2 3 0 0
# 2 4 0 0
# 3 1 1 0
# 3 2 0 1
# 3 3 0 1
# 4 1 1 0
# 4 2 1 0
# 5 1 1 0
# 5 2 0 1
# 5 3 1 0