我在rails应用程序中使用devise进行身份验证一切正常,但我有一个帖子模型,并且在我尝试创建新帖子后注册后显示错误:
1 error prohibited this post from being saved:
User must exist
我看了看终端并得到了这个:
Unpermitted parameter: user_id
(0.0ms) begin transaction
(0.0ms) rollback transaction
我尝试添加用户控制器 的 users_controller.rb
class UsersController < ApplicationController
before_action :authenticate_user!
before_action :set_user
before_action :check_ownership, only: [:edit, :update]
respond_to :html, :js
# GET /users
# GET /users.json
def index
@users = User.all
end
# GET /users/1
# GET /users/1.json
def show
end
# GET /users/new
def new
@user = User.new
end
# GET /users/1/edit
def edit
end
# POST /users
# POST /users.json
def create
@user = User.new(user_params)
respond_to do |format|
if @user.save
format.html { redirect_to @user, notice: 'User was successfully created.' }
format.json { render action: 'show', status: :created, location: @user }
else
format.html { render action: 'new' }
format.json { render json: @user.errors, status: :unprocessable_entity }
end
end
end
# PATCH/PUT /users/1
# PATCH/PUT /users/1.json
def update
respond_to do |format|
if @user.update(user_params)
format.html { redirect_to @user, notice: 'User was successfully updated.' }
format.json { head :no_content }
else
format.html { render action: 'edit' }
format.json { render json: @user.errors, status: :unprocessable_entity }
end
end
end
# DELETE /users/1
# DELETE /users/1.json
def destroy
@user.destroy
respond_to do |format|
format.html { redirect_to users_url }
format.json { head :no_content }
end
end
private
# Use callbacks to share common setup or constraints between actions.
def set_user
@user = User.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def user_params
params.require(:user).permit(:name, :email)
end
end
my posts_controler.rb
class PostsController < ApplicationController
before_action :authenticate_user!, :except => [:show, :index]
before_action :set_post, only: [:show, :edit, :update, :destroy]
# GET /posts
# GET /posts.json
def index
@posts = Post.all
end
# GET /posts/1
# GET /posts/1.json
def show
end
# GET /posts/new
def new
@post = Post.new
end
# GET /posts/1/edit
def edit
end
# POST /posts
# POST /posts.json
def create
@post = Post.new(post_params)
respond_to do |format|
if @post.save
format.html { redirect_to @post, notice: 'Post was successfully created.' }
format.json { render :show, status: :created, location: @post }
else
format.html { render :new }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
end
# PATCH/PUT /posts/1
# PATCH/PUT /posts/1.json
def update
respond_to do |format|
if @post.update(post_params)
format.html { redirect_to @post, notice: 'Post was successfully updated.' }
format.json { render :show, status: :ok, location: @post }
else
format.html { render :edit }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
end
# DELETE /posts/1
# DELETE /posts/1.json
def destroy
@post.destroy
respond_to do |format|
format.html { redirect_to posts_url, notice: 'Post was successfully destroyed.' }
format.json { head :no_content }
end
end
private
# Use callbacks to share common setup or constraints between actions.
def set_post
@post = Post.find(params[:id])
end
# Never trust parameters from the scary internet, only allow the white list through.
def post_params
params.require(:post).permit(:tittle, :body)
end
end
我的用户模型
class User < ApplicationRecord
# Include default devise modules. Others available are:
# :confirmable, :lockable, :timeoutable and :omniauthable
devise :database_authenticatable, :registerable,
:recoverable, :rememberable, :trackable, :validatable
has_many :posts
end
我的帖子模型
class Post < ApplicationRecord
belongs_to :user
end
我还通过此迁移向用户添加了user_id:
class AddUseridToPost < ActiveRecord::Migration[5.0]
def change
add_column :posts, :user_id, :integer
end
end
答案 0 :(得分:2)
如错误所示,允许user_id
如下
def post_params
params.require(:post).permit(:tittle, :body, :user_id)
end
或者,更好的方法是为post_in用户生成一个新帖子,如post post:
def create
@post = current_user.posts.new(post_params)
# ...other logic
end
这样,您也不需要允许user_id
,它将确保参数不会被篡改..
答案 1 :(得分:0)
如果在模型中添加列,则应将其添加到允许的参数中。因此,在:user_id
中允许的参数中添加posts_controller
:
def post_params
params.require(:post).permit(:tittle, :body, :user_id)
end