Question

我想执行一个sqlite查询：

c =  db.rawQuery("SELECT " + KEY_BOOK_ID+ " , " + KEY_BOOK_CODE  + " , " + KEY_ISBN + " , " +
                 KEY_VOL_NO  + " , " + KEY_BRAND  + " , " + KEY_SKU + " , " + KEY_TITLE +
                 " , " + KEY_PRICE + " , " + KEY_LANG + " , " + KEY_STATUS + " FROM " +
                 BOOKS_TABLE + " WHERE " + KEY_SKU + " IN " + inClause + ";", null);

in子句中的值需要从字符串数组中获取：

String values[] = {"Singles","5 in 1 series","Childrens Book"};

以下是我的错误日志。

引起：android.database.sqlite.SQLiteException：near＆＃34; 1＆＃34;：语法错误（代码1）:,编译时：SELECT book_id，book_code， ISBN，vol_no，品牌，sku，标题，价格，lang，状态FROM books_table WHERE sku IN（单打，5合1系列，儿童读物）; 在 android.database.sqlite.SQLiteConnection.nativePrepareStatement（母语方法）在 android.database.sqlite.SQLiteConnection.acquirePreparedStatement（SQLiteConnection.java:1112）在 android.database.sqlite.SQLiteConnection.prepare（SQLiteConnection.java:689）在 android.database.sqlite.SQLiteSession.prepare（SQLiteSession.java:588）在android.database.sqlite.SQLiteProgram。（SQLiteProgram.java:58）在android.database.sqlite.SQLiteQuery。（SQLiteQuery.java:37）在 android.database.sqlite.SQLiteDirectCursorDriver.query（SQLiteDirectCursorDriver.java:44）在 android.database.sqlite.SQLiteDatabase.rawQueryWithFactory（SQLiteDatabase.java:1433）在 android.database.sqlite.SQLiteDatabase.rawQuery（SQLiteDatabase.java:1372）

这是我调用以获取Json对象的方法。

public JSONObject searchForBooks( )
{
    String values[] = {"Singles","5 in 1 series","Childrens Book"};
    String inClause = Arrays.toString(values);

    //replace the brackets with parentheses
    inClause = inClause.replace("[","(");
    inClause = inClause.replace("]",")");

    SQLiteDatabase db = this.getReadableDatabase();
    Cursor c ;
    c =  db.rawQuery("SELECT " +KEY_BOOK_ID+ " , " + KEY_BOOK_CODE  + " , " + KEY_ISBN +
                " , " + KEY_VOL_NO  + " , " + KEY_BRAND  + " , " + KEY_SKU + " , " +
                KEY_TITLE + " , " + KEY_PRICE+ " , " + KEY_LANG+ " , " + KEY_STATUS
                + " FROM " + BOOKS_TABLE + " WHERE " + KEY_SKU + " IN " + inClause + ";",
                null);

    if (c.moveToFirst()) {
        do {
            JSONObject jobj = new JSONObject();
            try {
                jobj.put("book_id", c.getString(0));
                jobj.put("book_code", c.getString(1));
                jobj.put("ISBN", c.getString(2));
                jobj.put("vol_no", c.getString(3));
                jobj.put("brand", c.getString(4));
                jobj.put("sku", c.getString(5));
                jobj.put("title", c.getString(6));
                jobj.put("price", c.getString(7));
                jobj.put("lang", c.getString(8));
                jobj.put("status", c.getString(9));

                jarr1.put(0, jobj);
                jm1.put("books_info", jarr1);

                Log.d("Selected BOOKS info", jm1.toString());

            } catch (JSONException e) {
                e.printStackTrace();
            }
        } while (c.moveToNext());
    }
    c.close();
    db.close();

    return jm1;
}

感谢任何帮助或建议。谢谢。

Answer 1

你错过了这些字符串的引号。

我会以稍微不同的方式构建in子句

page_load

修改

要避免什么CL。在他的评论中描述，你可以替换

String values[] = {"Singles","5 in 1 series","Childrens Book"}; boolean first = true; String inClause = "("; for(String v : values){ if(first){ first = false; } else { inClause += "," } inClause += "'" + v + "'"; } inClause += ")";

与

inClause += "'" + v.replaceAll("'", "''") + "'";

这样一来，如果你的字符串中有单引号，它们将被转义，不会弄乱最终的查询。

Sqlite IN子句无法使用android中的数组值？

1 个答案: