Question

我尝试合并两个SELECT请求并将其分组到相同的属性中。

我有两个包含很多属性的表，有些是共同的（或者在＃34;人类语言和＃34中具有相同的含义）。

我已经尝试了CROSS JOIN和SELECT * FROM table1 (SELECT * FROM TABLE2))，但它无法正常工作。

例如：

表1：

{[Attribute1 = "Name1", 
 Attribute2 = age1, 
 Attribute3 = "Bla", 
 Attribute4 = "Blabla",  
 Attribute5 = 153, 
 Attribute6 = "something"] , 
 [Attribute1=....,....], ...}

表2：

{[Attribute1="Name25", 
 NotInterestingAttribute1="blabla", 
 Attribute15=125, 
 Attribute18="somethingElse"], 
 [Attribute1=....], ...}

我的目标是获得类似

的东西

FinalTable：

{[Attribute1="Name1", Attribute2=125, Attribute3="something"] , 
 [Attribute1="Name25", Attribute2=153, Attribute3="somethingElse"]}

我很抱歉，我试图制作一些真正的桌子，但我失败了。

我不知道我是否足够清楚，如果我没有，请告诉我。

感谢您的帮助！

编辑：

这是我目前正在尝试使用的SELECT请求：

SELECT Attribute1 as Attribute1, 
       Attribute5 as Attribute2, 
       Attribute15 as Attribute2, 
       Attribute6 as Attribute3, 
       Attribute18 as Attribute3 
FROM   Table1, Table2 
WHERE  Attribute1 like '%name%';

Answer 1

您正在寻找UNION ALL

SELECT Attribute1 as Attribute1, Attribute5 as Attribute2, Attribute15 as Attribute2, Attribute6 as Attribute3, Attribute18 as Attribute3 
FROM Table1
WHERE Attribute1 like '%name%'
UNION ALL
SELECT Attribute1 as Attribute1, Attribute5 as Attribute2, Attribute15 as Attribute2, Attribute6 as Attribute3, Attribute18 as Attribute3 
FROM Table2
WHERE Attribute1 like '%name%'

但是如果每个表上的字段名称不同，则使用别名，以便它们在同一字段上对齐

SELECT Attribute1 as Attribute1, Attribute5 as Attribute2, Attribute6 as Attribute3
FROM Table1
WHERE Attribute1 like '%name%'
UNION ALL
SELECT Attribute1 as Attribute1, Attribute15 as Attribute2, Attribute18 as Attribute3 
FROM Table2
WHERE Attribute1 like '%name%'

使用相同的属性名称分组SELECT请求

1 个答案: