我在CakePHP 3.4工作
我有两个模型skills
和skill_categories
,他们的关联就像
skill_categories->hasMany('skills');
skills->belongsTo('SkillCategories', 'joinType' => 'INNER')
和skills
与users
skills->belongsTo('users')
users->hasMany('Skills')
我必须从skills
skills
分组选择skills.skill_category_id
用户的所有关联Skill Category 1
|-- Skill 11
|-- Skill 12
|-- Skill 13
Skill Category 2
|-- Skill 21
|-- Skill 22
,这将产生类似
'skill_categories' => [
'title' => 'Skill Category 1',
'id' => 1,
'skills' => [
0 => [
'title' => 'Skill 11',
'id' => 4,
],
1 => [
'title' => 'Skill 12',
'id' => 6,
]
],
]
或喜欢
$user_skills = $this->Skills->find()
->select(['Skills.skill_category_id', 'Skills.title', 'Skills.measure', 'SkillCategories.title', 'Skills.id'])
->where(['Skills.user_id' => $user->id, 'Skills.deleted' => false, 'Skills.status' => 0])
->contain(['SkillCategories'])
->group(['Skills.skill_category_id']);
foreach($user_skills as $s)debug($s);
我正在做的是:方法1
$user_skills = $this->SkillCategories->find()
->where(['Skills.user_id' => $user->id, 'Skills.deleted' => false, 'Skills.status' => 0])
->contain(['Skills'])
->group(['SkillCategories.id']);
foreach($user_skills as $s)debug($s);
但是这会引发错误
错误:SQLSTATE [42000]:语法错误或访问冲突:1055 SELECT列表的表达式#2不在GROUP BY子句中并且包含 nonaggregated column' profPlus_db_new.Skills.title'不是 功能上依赖于GROUP BY子句中的列;这是 与sql_mode = only_full_group_by
不兼容
方法2
CREATE TABLE IF NOT EXISTS `skills` (
`id` CHAR(36) NOT NULL,
`user_id` CHAR(36) NOT NULL,
`skill_category_id` CHAR(36) NOT NULL,
`title` VARCHAR(250) NOT NULL,
`measure` INT NOT NULL DEFAULT 0,
`status` INT NULL DEFAULT 0,
`deleted` TINYINT(1) NULL DEFAULT 0,
`created` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
`modified` DATETIME NULL,
PRIMARY KEY (`id`)
)
但这会产生错误
错误:SQLSTATE [42S22]:找不到列:1054未知列 ' Skills.user_id'在' where子句'
<小时/> 编辑2
技能架构
CREATE TABLE IF NOT EXISTS `skill_categories` (
`id` CHAR(36) NOT NULL,
`title` VARCHAR(200) NOT NULL,
`status` INT NULL DEFAULT 0,
`deleted` TINYINT(1) NULL DEFAULT 0,
`created` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
`modified` DATETIME NULL,
PRIMARY KEY (`id`))
skill_categories架构
$user_skills = $this->SkillCategories->find()
->contain([
'Skills' => function($q) use($user) {
return $q
->select(['id', 'skill_category_id', 'title', 'measure', 'user_id', 'deleted', 'status'])
->where(['user_id' => $user->id, 'deleted' => false, 'status' => 0]);
}])
->group(['SkillCategories.id']);
foreach($user_skills as $s)debug($s);
控制器代码
object(App\Model\Entity\SkillCategory) {
'id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
'title' => 'Programming',
'status' => (int) 0,
'deleted' => false,
'skills' => [
(int) 0 => object(App\Model\Entity\Skill) {
'id' => '36f16f7f-b484-4fd8-bfc5-4408ce97ff23',
'skill_category_id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
'title' => 'PHP',
'measure' => (int) 92,
'user_id' => '824fbcef-cba8-419e-8215-547bd5d128ad',
'deleted' => false,
'status' => (int) 0,
'[repository]' => 'Skills'
},
(int) 1 => object(App\Model\Entity\Skill) {
'id' => '4927e7c1-826a-405d-adbe-e8c084c2b9ef',
'skill_category_id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
'title' => 'CakePHP',
'measure' => (int) 90,
'user_id' => '824fbcef-cba8-419e-8215-547bd5d128ad',
'deleted' => false,
'status' => (int) 0,
'[repository]' => 'Skills'
}
],
'[repository]' => 'SkillCategories'
}
object(App\Model\Entity\SkillCategory) {
'id' => 'd55a2a95-05a0-410e-9a55-1a1509f76b8c',
'title' => 'Office',
'status' => (int) 0,
'deleted' => false,
'skills' => [],
'[repository]' => 'SkillCategories'
}
调试输出
skills
注意:查看标题为 Office 的第二个对象与用户无关联PreserveAttribute
答案 0 :(得分:1)
您可以将条件传递给包含! :d
$user_skills = $this->SkillCategories->find()
->contain(['Skills' => function($q) use($user) {
return $q
->select(['id', 'user_id', 'deleted', 'status', 'skill_category_id'])
->where(['user_id' => $user->id, 'deleted' => false, 'status' => 0]);
}])
->group(['SkillCategories.id']);