我有一个跟随嵌套
的场景--Orders (List)
----Products (List)
------Manufacturers (List)
FIELDS
-Name
-Address
-City
在这种情况下,我需要执行查询,该查询将过滤制造商的城市并返回Orders, Products & only matching city manufacturers
我尝试进行以下查询,但即使城市与制造商不匹配,我也会获得产品的所有列表。
var filteredOrders = from o in Orders
from t in o.Products
where t.Manufacturers.Any(v => v.City == "Hartford")
select o;
即使我从select o
更改为'选择t.Manufacturers'无论城市过滤器如何,我都会获得所有制造商名单。
幸运的是,我得到了与我的场景相匹配的W3school SQL样本。 What is the difference between == vs equals() in Java?
SQL查询:
SELECT o.OrderId, p.ProductName, s.*
FROM [Orders] o
JOIN OrderDetails od ON o.OrderId = od.OrderId AND o.orderId = 10248
JOIN Products p ON od.ProductId = p.ProductId
JOIN Suppliers s ON p.SupplierId = s.SupplierId and s.City ='Singapore'
答案 0 :(得分:4)
我会压扁所有内容,然后只过滤你想要的城市:
class Manufacturer
{
public string Name;
public string Address;
public string City;
}
class Product
{
public Manufacturer[] Manufacturers;
}
class Order
{
public Product[] Products;
}
static void Main(string[] args)
{
var cities = new string[] { "a", "b" };
Order[] orders = null;
orders.SelectMany(o => o.Products.SelectMany(p => p.Manufacturers.Select(m => new { o, p, m })))
.Where(g => cities.Contains(g.m.City))
.ToList();
}
或者,如果您想要返回新 Order
(因为它们有不同的Products
,它必须指向新分配的Object
)您可以改为:
var newOrders = orders.Select(o => new Order()
{
Products = o.Products
.Select(p => new Product()
{
Manufacturers = p.Manufacturers.Where(m => cities.Contains(m.City)).ToArray()
})
.Where(m => m.Manufacturers.Length > 0).ToArray()
}).Where(p => p.Products.Length > 0).ToArray();
答案 1 :(得分:0)
您正在应用错误的城市过滤器。就是这条线。
where t.Manufacturers.Any(v => v.City == "Hartford")
Any
返回true
,至少有一家制造商拥有City的财产作为" Hartford"所以基本上你的查询是这样的
var filteredOrders = from o in Orders
from t in o.Products
where true//←This is the problem
select o;
你需要做的事实上是
where t.Manufacturers.City == "Hartford"
我希望这会有所帮助
示例:
var cityNames = new List<string> {"New York",
"Atlanta",
"Hartford",
"Chicago"
};
var anyResult = cityNames.Any(x=>x== "Hartford"); //TRUE
var whereResult = cityNames.Where(x => x == "Hartford"); //IEnumerable<string>, in this case only one element
答案 2 :(得分:0)
我无法想到一种可以完全避免创建新对象的方法,因为无法直接过滤父对象的list属性。你可以使用同一个类。
另外,我使用两个单独的查询来在父/祖父对象中创建一个新列表。
我做了一个小演示来演示这个想法(下面有相同的代码): http://ideone.com/MO6M6t
我尝试选择的城市是"tmp"
,仅在父p3
下,只属于祖父g1
,g3
预期输出为:
g1
p3
tmp
g3
p3
tmp
using System;
using System.Collections.Generic;
using System.Linq;
public class Test
{
public class GrandParent{
public List<Parent> parentList{ get; set; }
public string name{ get; set; }
public GrandParent(string name){
this.name = name;
this.parentList = new List<Parent>();
}
}
public class Parent{
public List<Child> childList{ get; set;}
public string name{ get; set; }
public Parent(string name){
this.name = name;
this.childList = new List<Child>();
}
}
public class Child{
public string city{ get; set;}
public Child(string city){
this.city = city;
}
}
public static void Main()
{
Child c1 = new Child("ABC"), c2 = new Child("123"), c3 = new Child("tmp");
Parent p1 = new Parent("p1"), p2 = new Parent("p2"), p3 = new Parent("p3");
GrandParent g1 = new GrandParent("g1"), g2 = new GrandParent("g2"), g3 = new GrandParent("g3");
p1.childList.Add(c1); p1.childList.Add(c2);
p2.childList.Add(c2);
p3.childList.Add(c3);
g1.parentList.Add(p1); g1.parentList.Add(p2); g1.parentList.Add(p3);
g2.parentList.Add(p2);
g3.parentList.Add(p3);
List<GrandParent> repo = new List<GrandParent>{g1, g2, g3};
var filteredParents = from g in repo
from p in g.parentList
where p.childList.Any(c => c.city == "tmp")
select new Parent(p.name){
childList = p.childList.Where(c => c.city == "tmp").ToList()
};
var filteredGrandParents = from g in repo
from p in g.parentList
where filteredParents.Any(fp => fp.name == p.name)
select new GrandParent(g.name){
parentList = g.parentList.Where(pp => filteredParents.Any(fp => fp.name == pp.name)).ToList()
};
foreach(var g in filteredGrandParents){
Console.WriteLine(g.name);
foreach(var p in g.parentList){
Console.WriteLine("\t" + p.name);
foreach(var c in p.childList){
Console.WriteLine("\t\t" + c.city);
}
}
Console.WriteLine();
}
}
}
答案 3 :(得分:0)
我终于尝试将所有内容放在一起并获得了预期的输出。
var fp = orders.Select(o =>
{
o.products = o.products.Select(p =>
{
p.manufacturers.RemoveAll(m => m.City != "Hartford");
return p;
}).ToList();
return o;
});
请建议是否有人有更好的解决方案