Question

以下代码应显示随机引用。但它什么也没有回来。只显示html页面布局。为什么跟随javascript回调函数不起作用：

＆＃13;

$(document).ready(function() {
  function cb() {
    var addr = "http://quotesondesign.com/wp-json/posts?filter[orderby]=rand&filter[posts_per_page]=1";
    $.getJSON(addr, function(rslt) {
      return rslt;
    });
  };

  function qte(rslt) {
    $("#qti").html(rslt[0].content);
    $("#athr").html(rslt[0].title);
  };
  qte(cb);
  $("#nqt").on("click", function() {
    qte(cb);
  });
  $("#tit").on("click", function() {
    window.open("https://twitter.com/intent/tweet?text=" + encodeURIComponent(qwe));
  });
});

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container-fluid">
  <h1 class="text-center" style="margin-top:20px;">Random Quote Generator</h1>
  <div class="box">
    <div class="qt">
      <span id="qti"></span>
    </div>
    <div class="athr">- <span id="athr"></span></div>
    <div style="width:100%; clear:both; margin-left:auto; margin-right:auto; margin-top:6%;">
      <button class="btn" title="twitt it!" id="tit"><i class="fa fa-twitter"></i></button>
      <button class="btn pull-right" id="nqt">New Quote</button>
    </div>
  </div>
</div>

＆＃13;

Answer 1

你可以这样做。一旦异步调用可以获得响应，请使用$.when触发qte函数。

$(document).ready(function() {
  function cb() {
    // changed http to https to avoid blockrd content
    var addr = "https://quotesondesign.com/wp-json/posts?filter[orderby]=rand&filter[posts_per_page]=1";
   // returning the 'promise' from this function
   return $.getJSON(addr, function(rslt) {
    return rslt;
    });
  };

  // when cb function has finished execution using its result to populate the fields
  $.when(cb()).done(function(rslt){

   $("#qti").html(rslt[0].content);
    $("#athr").html(rslt[0].title);
  });
  // rst of code
});

DEMO

回调函数在以下代码中不起作用？

1 个答案: