Question

我有一个字典，其中包含键作为单词，值包含数字。

  | A          | B          | C               |
  |------------+------------+-----------------|
 1| Submitting | Lookup     | Selling Windows |
  |------------+------------+-----------------|
 2| 13/07/2016 | 13/07/2016 | 27/07/2016      |
 3| 14/07/2016 | 27/07/2016 | 13/07/2016      |
 4| 15/07/2016 | 27/07/2016 |                 |
 5| 16/07/2016 | 27/07/2016 |                 | 
 6| 17/07/2016 | 27/07/2016 |                 |
 7| 18/07/2016 | 27/07/2016 |                 |
 8| 19/07/2016 | 27/07/2016 |                 |
 9| 20/07/2016 | 27/07/2016 |                 |
10| 21/07/2016 | 27/07/2016 |                 |
11| 22/07/2016 | 27/07/2016 |                 |
12| 23/07/2016 | 27/07/2016 |                 |
13| 24/07/2016 | 27/07/2016 |                 |
14| 25/07/2016 | 27/07/2016 |                 |
15| 26/07/2016 | 27/07/2016 |                 |
16| 27/07/2016 | 27/07/2016 |                 |

如何将键和值打印成两列，其中第二列的宽度为最长键，所有值都打印在右侧？

d = dict(bag.items())

我试过这个：

 10     potatoes
  8       tomato
  5        onion
  3        plate
  2          ham
  1         meat

但我必须找到一种方法来设置右侧的值，因此在键和值之间建立适当的空格。

Answer 1

建立最大宽度，format字符串：

mkey = max(map(len, (map(str, bag.keys()))))
mval = max(map(len, (map(str, bag.values()))))

for k, v in bag.items():
    print('  {:>{}}    {:>{}}'.format(k, mkey, v, mval))

Answer 2

我是这样做的：

bag = {'tomato': 15, 'onion': 3,'potatoes': 7, 'ham': 2}
bag_values = []

longest = ""
for k in bag:
    if len(k) > len(longest):
        longest = k

longest_v = ""
for k, v in bag.items():
    bag_values.append(str(v))

for value in bag_values:
    if len(value) > len(longest_v):
        longest_v = value

space = " "
a = (len(7*space)+len(longest_v)+len(longest))


for k, v in bag.items():
    c = len(longest) - len(k)
    b = len(longest_v) - len(str(v))
    print((3+b)*space + str(v) + (4+c)*space + k)

如何将值和键打印成两列，它们之间有适当的空间？

2 个答案: