假设我有以下输入字段:
<input id="inputField" type="number" value="">
和一些div如:
<div id="1000"></div>
<div id="1200"></div>
<div id="1500"></div>
<div id="1900"></div>
...
当用户在输入字段中输入数字时,我希望我的代码转到最接近该数字的div id。
例如:如果用户输入1300,则显示id为“1200”的div。
考虑到会有大量的div,在javascript中实现它的最有效方法是什么?
现在我正在做:
<script>
function myFunction()
{
var x = document.getElementById("inputField").value;
if(x >= 1750 && x <= 1900)
{
window.location.hash = '#1800';
}
}
</script>
答案 0 :(得分:2)
如果可以的话,一种方法是将所有带有数字ID的div包装在另一个div中(并给它一些id,比如说&#39;数字&#39;);这允许您在javascript文件中找到所有div。
// Get all the divs with numbers, if they are children of div, id="numbers"
let children = document.getElementById('numbers').children;
let array = [];
for (i = 0; i < children.length; i++) {
// Append the integer of the id of every child to an array
array.push(parseInt(children[i].id));
}
// However you are getting your input number goes here
let number = 1300 // Replace
currentNumber = array[0]
for (const value of array){
if (Math.abs(number - value) < Math.abs(number - currentNumber)){
currentNumber = value;
}
}
// You say you want your code to go to the nearest div,
// I don't know what you mean by go to, but here is the div of the closest number
let target = document.getElementById(currentNumber.toString());
如果有更多我可以添加帮助,请告诉我。
function closestNum() {
let children = document.getElementById('numbers').children;
let array = [];
for (i = 0; i < children.length; i++) {
array.push(parseInt(children[i].id));
}
let number = document.getElementById('inputnum').value;
currentNumber = array[0]
for (const value of array) {
if (Math.abs(number - value) < Math.abs(number - currentNumber)) {
currentNumber = value;
}
}
let target = document.getElementById(currentNumber.toString());
document.getElementById('target').innerHTML = target.innerHTML;
}
&#13;
<div id="numbers">
<div id="1000">1000</div>
<div id="2000">2000</div>
<div id="3000">3000</div>
<div id="4000">4000</div>
<div id="5000">5000</div>
</div>
<br />
<input type="text" id="inputnum" placeholder="Input Number" onchange="closestNum()" />
<br />
<br /> Target:
<div id="target"></div>
&#13;
答案 1 :(得分:1)
这可能对你有用。循环遍历每个div并将其与输入的ID进行比较。跟踪最近的一个,隐藏所有div,然后显示最接近的。
document.getElementById("inputField").addEventListener("change", function(){
var divs = document.getElementsByTagName("div");
var closestDiv = -1;
var inputId = document.getElementById("inputField").value;
for(var i=0; i<divs.length; i++)
{
if(Math.abs(inputId - closestDiv) > Math.abs(inputId - divs[i].id) || closestDiv == -1)
{
closestDiv = divs[i].id;
for (var x = 0; x < divs.length; x++) {
divs[x].style.display = 'none';
}
divs[i].style.display = "block";
}
}
});
直播: jsfiddle.net
答案 2 :(得分:1)
通过一些优化,这应该没问题 -
var element;
document.addEventListener("change",
function(evt){
if(element && element.classList){
element.classList.remove("selected", false);
element.classList.add("unselected", true);
}
var listOfDivs =
document.querySelectorAll(".unselected");
var val = evt.target.value;
var leastAbs=listOfDivs[0].id;
for(let anIndex=0, len=listOfDivs.length;anIndex<len;anIndex++){
if(Math.abs(listOfDivs[anIndex].id-val)<leastAbs){
leastAbs = Math.abs(listOfDivs[anIndex].id-val);
element = listOfDivs[anIndex];
}
}
element.classList.remove("unselected");
element.classList.add("selected");
});
.selected{
background-color:red;
}
.unselected{
background-color:yellow;
}
.unselected, .selected{
width:100%;
height:50px;
}
<input id="inputField" type="number" value="">
<div id="1000" class='unselected'>1</div>
<div id="1200" class='unselected'>2</div>
<div id="1500" class='unselected'>3</div>
<div id="1900" class='unselected'>4</div>