我正在学习斯威夫特。我有一个问题。
问题 - 我有带图片网址的DataModel,所以第一次会从网址下载图片,当然第二次会赢得#t。因此,当我在块中获取图像时,我想用图像更新我的数据模型。但它不起作用。
ViewController.swift
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "OffersTableCell", for: indexPath) as! OffersTableCell
var model = offersArray[indexPath.row] as! OffersModel
cell.updateOfferCellWith(model: model, completionHandler: { image in
model.image = image
})///// I am getting image here, but model is not getting update
return cell
}
Cell.Swift
func updateOfferCellWith(model: OffersModel, completionHandler:@escaping (UIImage) -> Void) {
if (model.image != nil) { //Second time this block should be execute, but model image is always nil
DispatchQueue.main.async { [weak self] in
self?.offerImageView.image = model.image
}
}
else{
//First time- Download image from URL
ImageDownloader.downloadImage(imageUrl: model.offerImageURL) { [weak self] image in
DispatchQueue.main.async {[model] in
var model = model
self?.offerImageView.image = image
//model.image = image*//This is also not working*
completionHandler(image)*//Call back*
}
}
}
}
答案 0 :(得分:0)
下面是一个基于你的代码的潜在解决方案,但是,正如vadain在评论中所说,有点危险,因为图像加载是异步的,并且可能在单元格不再存在时返回图像。
理想情况下,您要做的是以持久的方式设置模型,并发送异步请求以下载它的图像。然后,当图像返回时,它会更新模型,模型会广播一条消息,说明它的图像已经更新。当模型存在时,单元可以监听并响应模型的更新。
func tableView(_ tableView:UITableView,cellForRowAt indexPath:IndexPath) - > UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "OffersTableCell", for: indexPath) as! OffersTableCell
var model = offersArray[indexPath.row] as! OffersModel
if image = model.image {
// setting directly here... you could call an image on the cell if you want more data encapuslation
cell.offerImageView.image = model.image
} else {
ImageDownloader.downloadImage(imageUrl: model.offerImageURL) { [weak self] image in
DispatchQueue.main.async {
model.image = image
cell.offerImageView.image = image
}
}
}
return cell
}