我试图将整个file.txt读入一个char数组。但是有一些问题,建议请=]
ifstream infile;
infile.open("file.txt");
char getdata[10000]
while (!infile.eof()){
infile.getline(getdata,sizeof(infile));
// if i cout here it looks fine
//cout << getdata << endl;
}
//but this outputs the last half of the file + trash
for (int i=0; i<10000; i++){
cout << getdata[i]
}
答案 0 :(得分:3)
std::ifstream infile;
infile.open("Textfile.txt", std::ios::binary);
infile.seekg(0, std::ios::end);
size_t file_size_in_byte = infile.tellg();
std::vector<char> data; // used to store text data
data.resize(file_size_in_byte);
infile.seekg(0, std::ios::beg);
infile.read(&data[0], file_size_in_byte);
答案 1 :(得分:3)
使用std::string
:
std::string contents;
contents.assign(std::istreambuf_iterator<char>(infile),
std::istreambuf_iterator<char>());
答案 2 :(得分:2)
如果您计划将整个文件吸入缓冲区,则无需逐行读取。
char getdata[10000];
infile.read(getdata, sizeof getdata);
if (infile.eof())
{
// got the whole file...
size_t bytes_really_read = infile.gcount();
}
else if (infile.fail())
{
// some other error...
}
else
{
// getdata must be full, but the file is larger...
}
答案 3 :(得分:1)
每次阅读新行时,都会覆盖旧行。保留索引变量i并使用infile.read(getdata+i,1)
然后递增i。
答案 4 :(得分:0)
您可以使用Tony Delroy的答案并合并一个小函数来确定文件的大小,然后创建该大小的char
数组,如下所示:
//Code from Andro in the following question: https://stackoverflow.com/questions/5840148/how-can-i-get-a-files-size-in-c
int getFileSize(std::string filename) { // path to file
FILE *p_file = NULL;
p_file = fopen(filename.c_str(),"rb");
fseek(p_file,0,SEEK_END);
int size = ftell(p_file);
fclose(p_file);
return size;
}
然后您可以执行以下操作:
//Edited Code From Tony Delroy's Answer
char getdata[getFileSize("file.txt")];
infile.read(getdata, sizeof getdata);
if (infile.eof()) {
// got the whole file...
size_t bytes_really_read = infile.gcount();
}
else if (infile.fail()) {
// some other error...
}