Question

我成功启动并运行了websocket，但我需要在路线上使用.send()方法。

我的应用程序拆分了几个文件。在这种情况下，我得到了：

app.js

//..some other code..

//Server

const server = http.createServer(app)
var port = process.env.PORT || 80;
const connection = server.listen(port, () => {
  console.log('Listening on ' + port);
});


const WebSocketServer = require("ws").Server;
const wss = new WebSocketServer({
  server
});

//Here I need to export the wss

module.exports.sengMsg = function (msg, callback) {
  return wss.on("connection", function (ws) {

    ws.send(msg, callback);


    ws.on("close", function () {
      console.log("websocket connection close")
    })
  })
};

api.js

//..some other code..

var sendMsg = require('../app').sendMsg;


router.get('/', (req, res) => {
    sendMsg('Hi I from default route', (err)=>{
       console.log("I got some error on ws");
    })
    res.send('Welcome to my API');

})

但最后我想出了

TypeError：sendMsg不是函数

使用此设置在我的路线上导出wss的功能的推荐方法是什么？

Answer 1

尝试将代码更改为

var sendMsg = require('./app');

router.get('/', (req, res) => {
   sendMsg.sendMsg('Hi I from default route', (err)=>{
   console.log("I got some error on ws");
   })
   res.send('Welcome to my API');

})

或将app.js module.exports更改为以下内容，

module.exports = {
sendMessage :function (msg, callback) {
    return wss.on("connection", function (ws) {

        ws.send(msg, callback);


        ws.on("close", function () {
            console.log("websocket connection close")
        })
    })
}
}

Websockets ws - Node＆amp; Express - 导出API

1 个答案: