Question

如果我的第二个输入是星期日，则日历只能正常工作。我如何使它实际上空间到正确的一天？有没有办法让代码更简单，更好，更少混淆，并使日历的格式看起来更好？

#include<stdio.h>

int main()
{
    int i,number,startday;

    //getting user input
    printf("Enter Total Number of Day in the Month:",number);
    scanf("%d", &number);
    printf("Enter Starting Day of The Month (0-6 Sunday-Saturday):",startday);
    scanf("%d", &startday);

    //formatting
    printf("   Sun  Mon  Tue  Wed  Thu  Fri  Sat \n");
    printf("_______________________________________ \n");

    //loop
    for(i=1;i<=number;i++)
      {
        printf("%5d", i);
        if(i == 7 || i == 14 || i == 21 || i == 28)
        {
          printf("\n");
          printf("\n");
        }
      }
    //formatting
    printf("\n_______________________________________");
    return 0;
}

Answer 1

首先阅读并了解printf()和scanf()的真实格式 image from a journal。

你写道：

printf("Enter Total Number of Day in the Month:",number);

应该是：

printf("Enter Total Number of Day in the Month: ");

并且您的来源几乎没有变化：

#include <stdio.h>

int main(void)
{
    int i, number, startday;

    //getting user input
    printf("Enter Total Number of Day in the Month: ");
    scanf("%d", &number);
    printf("Enter Starting Day of The Month (0-6 Sunday-Saturday): ");
    scanf("%d", &startday);

    //formatting
    printf("  Sun  Mon  Tue  Wed  Thu  Fri  Sat\n");
    printf("______________________________________\n");

    ///fill calendar with proper space "  "
    i=0;
    while (i<startday){
        printf("%5c", ' ');
        i++;
    }

    for(i=1;i<=number;i++){
        printf("%5d", i);

        if((startday+i)%7==0){
            printf("\n\n");
        }
    }

    //formatting
    printf("\n_______________________________________\n");

    return 0;
}

此代码有效，但我建议您检查用户输入在整数数据类型和真实范围内具有适当的格式使用简单if (day < 28 || day > 31)或if (startday < 0 || startday > 6)，并检查每个scanf()是否成功，如果不成功，可能会退出（带有消息）。

使用C的日历 - 无法使其工作

1 个答案: