如Documentation中所述,可以将可重用的组件(如lineSink)写入文件中。
我想知道如何从文档中重写lineSink
组件,以便能够实现以下场景:
val source = Source(1 to 10)
val flow = Flow[Int].map(_.toString)
/** Rewrite of the lineSink to enable new files with content */
val fileSink = Sink[String, Future[IOResult]] =
Flow[String]
.map(s => ByteString(s + "\n"))
.toMat(FileIO.toPath(Paths.get(filename)))(Keep.right)
/** After running the graph i want to have a new file for each item processed */
val graph = source.via(flow).to(sink)
答案 0 :(得分:2)
您将需要为每个新传入元素实现一个新流。当Animation
接收器具体化为FileIO.toPath
时,您可以使用Future
(具有合理的并行选择)来实现此目的。见下面的例子:
mapAsync
请注意,您需要为每个传入元素生成适当的 val source = Source(1 to 10)
val flow: Flow[Int, String, NotUsed] = Flow[Int].map(_.toString)
val fileFlow: Flow[String, IOResult, NotUsed] =
Flow[String].mapAsync(parallelism = 4){ s ⇒
Source.single(ByteString(s)).runWith(FileIO.toPath(Paths.get(fileName)))
}
val fileSink: Sink[IOResult, Future[Done]] = Sink.foreach[IOResult]{println}
val graph = source.via(flow).via(fileFlow).to(fileSink)
。你需要想出办法来做到这一点。