我尝试在可扩展列表中选择时删除组,并在删除后刷新列表。
我从谷歌获取了源代码:
我尝试了几种方法来删除它,但没有成功,任何人都已经实现了它?
谢谢, 射线。
答案 0 :(得分:3)
回答第二个问题(向子和数据结构添加行)
对于数据结构:
public class GroupItem {
private String mItemText;
private List<ChildItem> mChildItems=new ArrayList<ChildItem>();
public GroupItem(String itemText) {
mItemText=itemText;
}
public String getItemText() {
return mItemText;
}
public ChildItem getChild(int childPosition) {
return mChildItems.get(childPosition);
}
public void addChild(ChildItem childItem) {
return mChildItems.add(childItem)
}
public void removeChild(int childPosition) {
return mChildItems.remove(childPosition);
}
}
public class ChildItem {
private String mItemText;
public ChildItem(itemText) {
mItemText=itemText;
}
public String getItemText() {
return mItemText;
}
}
现在要设置它,你会做类似的事情:
List<GroupItem> items = new ArrayList<GroupItem>();
GroupItem item1 = new GroupItem("This is group 1");
item1.addChild(new ChildItem("This is a child item of group 1"));
item1.addChild(new ChildItem("This is another child item of group 1"));
依旧......
然后,在适配器中,您需要返回适当的数据。
关于行的问题: 在您的Google示例中,他们返回TextView。但是,您可以根据自己喜欢的内容制作自己的布局。例如:
<ImageView android:id="@+id/RowIcon"
android:layout_width="56px"
android:layout_height="56px"
android:layout_marginLeft="12px"
android:layout_marginTop="2px">
</ImageView>
<TextView android:id="@+id/RowTextView"
android:paddingLeft="10px"
android:paddingTop="10px"
android:layout_width="wrap_content"
android:layout_height="wrap_content" android:textColor="#666666" android:textSize="14px"/>
</LinearLayout>
然后在适配器中使用此布局。而不是返回,例如,TextView,您只需将其作为视图返回:
public View getChildView(int groupPosition, int childPosition, boolean isLastChild,
View convertView, ViewGroup parent) {
LayoutInflater mInflater = (LayoutInflater)mContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = mInflater.inflate(YOUR XML FILE FROM ABOVE, null);
ImageView rowIcon = (ImageView)rowView.findViewById(R.id.RowIcon);
iconType.setBackgroundResource(AN IMAGE HERE);
TextView rowText =(TextView)rowView.findViewById(R.id.RowTextView);
textAddress.setText(items.get(groupPosition).getChild(childPosition));
return rowView;
}
所以,我认为应该让你去。
另外,如果他们满意,请接受我的答案。
干杯。
答案 1 :(得分:1)
将功能添加到适配器以删除项目:
public void removeGroup(int group) {
//TODO: Remove the according group. Dont forget to remove the children aswell!
Log.v("Adapter", "Removing group"+group);
notifyDataSetChanged();
}
public void removeChild(int group, int child) {
//TODO: Remove the according child
Log.v("Adapter", "Removing child "+child+" in group "+group);
notifyDataSetChanged();
}
通过更改以下内容确保您可以访问新方法:
ExpandableListAdapter mAdapter;
到
MyExpandableListAdapter mAdapter;
在需要时调用方法:
@Override
public boolean onContextItemSelected(MenuItem item) {
ExpandableListContextMenuInfo info = (ExpandableListContextMenuInfo) item.getMenuInfo();
String title = ((TextView) info.targetView).getText().toString();
int type = ExpandableListView.getPackedPositionType(info.packedPosition);
if (type == ExpandableListView.PACKED_POSITION_TYPE_CHILD) {
int groupPos = ExpandableListView.getPackedPositionGroup(info.packedPosition);
int childPos = ExpandableListView.getPackedPositionChild(info.packedPosition);
mAdapter.removeChild(groupPos, childPos);
return true;
} else if (type == ExpandableListView.PACKED_POSITION_TYPE_GROUP) {
int groupPos = ExpandableListView.getPackedPositionGroup(info.packedPosition);
mAdapter.removeGroup(groupPos);
return true;
}
return false;
}
所以,希望有所帮助。干杯