Question

我有一个多维数组，我只想保留最重复的条目。我得到的最接近的是：

$wd = array_unique($arr);
$d = array_diff($arr, $wd);
print_r($d);

但这仅适用于单维数组并输出所有重复数据。我该怎么做呢？

所需输出的例子：

如果数组是：

array(
    [1] => ( 
        [u] => test1u 
        [d] => test1d
    ) 
    [2] => ( 
        [u] => test2u 
        [d] => test2d
    ) 
    [3] => ( 
        [3] => test3u 
        [3] => test3d
    ) 
    [1] => ( 
        [u] => test1u 
        [d] => test1d
    )
)

它应该返回array([1] => ( [u] => test1u [d] => test1d))

如果数组是：

array(
    [1] => ( 
        [u] => test1u 
        [d] => test1d
    ) 
    [2] => ( 
        [u] => test2u 
        [d] => test2d
    ) 
    [3] => ( 
        [3] => test3u 
        [3] => test3d
    ) 
    [1] => ( 
        [u] => test1u 
        [d] => test1d
    ) 
    [2] => ( 
        [u] => test2u 
        [d] => test2d
    )
)

它应该返回array([1] => ( [u] => test1u [d] => test1d)[2] => ( [u] => test2u [d] => test2d))

但是如果数组是：

array(
    [1] => ( 
         [u] => test1u 
         [d] => test1d
    ) 
    [2] => ( 
         [u] => test2u 
         [d] => test2d
    ) 
    [3] => ( 
         [3] => test3u 
         [3] => test3d
    ) 
    [1] => ( 
         [u] => test1u 
         [d] => test1d
    ) 
    [2] => ( 
         [u] => test2u 
         [d] => test2d
    ) 
    [1] => ( 
         [u] => test1u 
         [d] => test1d
    )
)

它应该只返回array([1] => ( [u] => test1u [d] => test1d))

编辑：

数组中有重复的条目，因为数组来自$arr = json_decode($arr);，原始JSON有重复的条目。如果有更好的方法可以在不解码json的情况下执行此操作，请告诉我。

这被用作搜索程序的一部分。 JSON是源数组中符合其中一个搜索项条件的所有条目的数组。保留具有最多重复项的条目可确保这些条目包含大多数（如果不是全部）搜索项。

这里是正在解码的JSON文件：

[{"1":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"roses","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"2":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"roses","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"5":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"roses daffodil","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"3":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"daffodil","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"4":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"daffodil","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"5":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"roses daffodil","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]},{"6":[{"u":"testing","d":"2017\/04\/27","st":"Test","i":"roses daffodil","v":"1","t":"org","sp":"N\/A","k":"0","img":"--"}]}]

在这种情况下，制作此JSON的搜索是针对“玫瑰水仙花”

Answer 1

它添加的第二个例子 - 每个索引只能出现一次。对于第一个这应该工作正常：

// <Name>Complex method must be covered by tests</Name>
warnif count > 0 
from m in Application.Methods
where m.PercentageCoverage < 80 &&
      m.CyclomaticComplexity > 10select new { 
   m,
   m.PercentageCoverage,
   m.CyclomaticComplexity,
   m.NbLinesOfCodeNotCovered,
   Debt = (10 + 3*(m.CyclomaticComplexity -10) + 4*m.NbLinesOfCodeNotCovered)
          .ToMinutes().ToDebt(),
   AnnualInterest = (20 + 2*(m.CyclomaticComplexity) + 6*m.NbLinesOfCodeNotCovered)
                    .ToMinutes().ToAnnualInterest()
}

不幸的是<?php $array[] = array( 'u' => 'test1u', 'd' => 'test1d' ); $array[] = array( 'u' => 'test2u', 'd' => 'test2d' ); $array[] = array( '3' => 'test3u', '3' => 'test3d' ); $array[] = array( 'u' => 'test1u', 'd' => 'test1d' ); $array[] = array( 'u' => 'test2u', 'd' => 'test2d' ); var_export( $array ); //echo("\n" . array_count_values($array) . "\n"); foreach( $array as $k => $v ){ foreach( $array as $ke => $ve ){ if( $k == $ke ) continue; if( $v == $ve ) { $d[$k]=$v; unset($array[$k]); } } } var_export( $d ); ?>仅适用于String和int，所以当你有复杂的值时它不起作用。

Answer 2

首先你的数组不能有相同的键。查看live demo。

<?php

$array[] = array( 'u' => 'test1u', 'd' => 'test1d' );
$array[] = array( 'u' => 'test2u', 'd' => 'test2d' );
$array[] = array( 'u' => 'test3u', 'd' => 'test3d' );
$array[] = array( 'u' => 'test1u', 'd' => 'test1d' );
$array[] = array( 'u' => 'test2u', 'd' => 'test2d' );

$array = array_map(function($v){return implode('-', $v);}, $array);
$count = array_count_values($array);
print_r($count);
arsort($count);
$max = current($count);
while(current($count) == $max)
{
    $arr = explode('-', key($count));
    $result[] = array('u' => $arr[0], 'd' => $arr[1]);
    next($count);
}
print_r($result);

Answer 3

我找到了解决方案！有点啰嗦，但它确实有效！

$json = json_decode($json);
$jsonoutc = $jsonout = "";
$arrid = $arrout = $disp = array();
foreach ($json as $null => $arr){
    foreach ($arr as $key => $null){
        $arrid[] = $key;
    }
}
$vals = array_count_values($arrid);
foreach ($vals as $val => $counted){
    if ($counted > $jsonoutc){
        $jsonoutc = $counted;

    }
}
foreach ($vals as $val => $counted){
    if ($counted == $jsonoutc){
        $arrout[] = $val;

    }
}
foreach ($arrout as $null => $val){
    foreach ($json as $null => $arr){
        foreach ($arr as $key => $list){
            if ($key == $val){
                $disp[$key] = $list;
            }
        }
    }
}
print_r($disp);

返回包含重复php的数组

3 个答案: