查询许多相同文件的简明方法

Question

是否有一种简洁的方法来编写一个查询来在40个相同的文件上运行相当于以下查询：

SELECT * FROM file1                       
where created > '2017-03-01-00.00.00.000000'
and regDate < 20170101

SELECT * FROM file2                       
where created > '2017-03-01-00.00.00.000000'
and regDate < 20170101

.
.
.

SELECT * FROM file40                       
where created > '2017-03-01-00.00.00.000000'
and regDate < 20170101

Answer 1

最好的答案似乎是：

with combinedFile as (  

SELECT * FROM file1

union all                                         
SELECT * FROM file02                          

.
.
.

union all                                         
SELECT * FROM file40 )                        


SELECT * FROM combinedFile                               
where created > '2017-03-01-00.00.00.000000'    
and regDate < 20170101                           

感谢所有帮助我通过发表评论来达到这个答案的人！