我一直收到错误:AttributeError: 'NodeList' object has no attribute 'data'
,但我只是想检查该节点是否为空,如果是,则只传递-1而不是值。我的理解是temp_pub.getElementsByTagName("pages").data
应该返回None
。我该如何解决这个问题?
(p.s.-我试过!= None
和is None
)
xmldoc = minidom.parse('pubsClean.xml')
#loop through <pub> tags to find number of pubs to grab
root = xmldoc.getElementsByTagName("root")[0]
pubs = [a.firstChild.data for a in root.getElementsByTagName("pub")]
num_pubs = len(pubs)
count = 0
while(count < num_pubs):
temp_pages = 0
#get data from each <pub> tag
temp_pub = root.getElementsByTagName("pub")[count]
temp_ID = temp_pub.getElementsByTagName("ID")[0].firstChild.data
temp_title = temp_pub.getElementsByTagName("title")[0].firstChild.data
temp_year = temp_pub.getElementsByTagName("year")[0].firstChild.data
temp_booktitle = temp_pub.getElementsByTagName("booktitle")[0].firstChild.data
#handling no value
if temp_pub.getElementsByTagName("pages").data != None:
temp_pages = temp_pub.getElementsByTagName("pages")[0].firstChild.data
else:
temp_pages = -1
temp_authors = temp_pub.getElementsByTagName("authors")[0]
temp_author_array = [a.firstChild.data for a in temp_authors.getElementsByTagName("author")]
num_authors = len(temp_author_array)
count = count + 1
正在处理的XML
<pub>
<ID>5010</ID>
<title>Model-Checking for L<sub>2</sub</title>
<year>1997</year>
<booktitle>Universität Trier, Mathematik/Informatik, Forschungsbericht</booktitle>
<pages></pages>
<authors>
<author>Helmut Seidl</author>
</authors>
</pub>
<pub>
<ID>5011</ID>
<title>Locating Matches of Tree Patterns in Forest</title>
<year>1998</year>
<booktitle>Universität Trier, Mathematik/Informatik, Forschungsbericht</booktitle>
<pages></pages>
<authors>
<author>Andreas Neumann</author>
<author>Helmut Seidl</author>
</authors>
</pub>
编辑完整代码(使用ElementTree)
#for execute command to work
import sqlite3
import xml.etree.ElementTree as ET
con = sqlite3.connect("publications.db")
cur = con.cursor()
from xml.dom import minidom
#use this to clean the foreign characters
import re
def anglicise(matchobj):
if matchobj.group(0) == '&':
return matchobj.group(0)
else:
return matchobj.group(0)[1]
outputFilename = 'pubsClean.xml'
with open('test.xml') as inXML, open(outputFilename, 'w') as outXML:
outXML.write('<root>\n')
for line in inXML.readlines():
if (line.find("<sub>") or line.find("</sub>")):
newline = line.replace("<sub>", "")
newLine = newline.replace("</sub>", "")
outXML.write(re.sub('&[a-zA-Z]+;',anglicise,newLine))
outXML.write('\n</root>')
tree = ET.parse('pubsClean.xml')
root = tree.getroot()
xmldoc = minidom.parse('pubsClean.xml')
#loop through <pub> tags to find number of pubs to grab
root2 = xmldoc.getElementsByTagName("root")[0]
pubs = [a.firstChild.data for a in root2.getElementsByTagName("pub")]
num_pubs = len(pubs)
count = 0
while(count < num_pubs):
temp_pages = 0
#get data from each <pub> tag
temp_ID = root.find(".//ID").text
temp_title = root.find(".//title").text
temp_year = root.find(".//year").text
temp_booktitle = root.find(".//booktitle").text
#handling no value
if root.find(".//pages").text:
temp_pages = root.find(".//pages").text
else:
temp_pages = -1
temp_authors = root.find(".//authors")
temp_author_array = [a.text for a in temp_authors.findall(".//author")]
num_authors = len(temp_author_array)
count = count + 1
#process results into sqlite
pub_params = (temp_ID, temp_title)
cur.execute("INSERT OR IGNORE INTO publication (id, ptitle) VALUES (?, ?)", pub_params)
cur.execute("INSERT OR IGNORE INTO journal (jtitle, pages, year, pub_id, pub_title) VALUES (?, ?, ?, ?, ?)", (temp_booktitle, temp_pages, temp_year, temp_ID, temp_title))
x = 0
while(x < num_authors):
cur.execute("INSERT OR IGNORE INTO authors (name, pub_id, pub_title) VALUES (?, ?, ?)", (temp_author_array[x],temp_ID, temp_title))
cur.execute("INSERT OR IGNORE INTO wrote (name, jtitle) VALUES (?, ?)", (temp_author_array[x], temp_booktitle))
x = x + 1
con.commit()
con.close()
print("\nNumber of entries processed: ", count)
答案 0 :(得分:0)
您可以使用attributes
方法获取类似字典的对象(Doc),然后查询字典:
if temp_pub.getElementsByTagName("pages").attributes.get('data'):
答案 1 :(得分:0)
正如错误消息所示getElementsByTagName()
既不返回单个节点也不返回None
,而是返回NodeList。因此,您应该检查长度以查看返回的列表是否包含任何项目:
if len(temp_pub.getElementsByTagName("pages")) > 0:
temp_pages = temp_pub.getElementsByTagName("pages")[0].firstChild.data
或者您可以将列表直接传递给if
,因为空列表是 falsy :
if temp_pub.getElementsByTagName("pages"):
temp_pages = temp_pub.getElementsByTagName("pages")[0].firstChild.data
旁注,尽管此问题的标题和标记,但您的代码建议您使用minidom
代替ElementTree
。使用ElementTree
可以更简单地编写代码,例如:
# minidom
temp_ID = temp_pub.getElementsByTagName("ID")[0].firstChild.data
# finding single element can be using elementtree's `find()`
temp_ID = temp_pub.find(".//ID").text
....
# minidom
temp_author_array = [a.firstChild.data for a in temp_authors.getElementsByTagName("author")]
# finding multiple elements using elementtree's `find_all()`
temp_author_array = [a.text for a in temp_authors.find_all(".//author")]