我有一个格式列表:
Apple, Orange[123 431]43351
Banana, Cherry[141 421]23423
Coconut, Mango[23 12312]232342
....
....
我想根据括号后的数字对列表进行排序']'。 输出应为:
Banana, Cherry[141 421]23423
Apple, Orange[123 431]43351
Coconut, Mango[23 12312]232342
我正在尝试使用以下方法对列表进行排序:
LIST.sort(key = lambda x: x.split()[1])
for item in LIST:
print(item)
我可以通过这个找到最后一个数字: 但我无法对其进行排序
for item in LIST:
bracket_index = item.find("]")
end_of_line = item[bracket_index + 1:]
if bracket_index != -1:
print(end_of_line)
答案 0 :(得分:2)
您的列表格式是什么?它是元组列表还是字符串列表?这有效:
a = ['Apple, Orange[123 431]43351',
'Banana, Cherry[141 421]23423',
'Coconut, Mango[23 12312]232342']
a.sort(key = lambda el: el.split(']')[1])
print(a)
Output:
['Coconut, Mango[23 12312]232342',
'Banana, Cherry[141 421]23423',
'Apple, Orange[123 431]43351']
如果它是一对字符串对,那么你应该使用key = lambda el: el[1].split(']')[1]
,如下所示:
a = [('Apple', 'Orange[123 431]43351'),
('Banana', 'Cherry[141 421]23423'),
('Coconut',' Mango[23 12312]232342')]
a.sort(key = lambda el: el[1].split(']')[1])
print(a)
Output:
[('Coconut', ' Mango[23 12312]232342'),
('Banana', 'Cherry[141 421]23423'),
('Apple', 'Orange[123 431]43351')]
答案 1 :(得分:0)
你可以参考@ Psidom的建议:
LIST.sort(key=lambda x: int(x.split(']')[1]))
注意使用int()
来确保排序是以数字方式而不是通过字符串比较(这是懒惰地完成;即,'4321'
被认为是“大于”由于'20000000'
)'4' > '2'
。{/ p>
完整示例:
LIST = [
'Apple, Orange[123 431]43351',
'Banana, Cherry[141 421]23423',
'Coconut, Mango[23 12312]232342'
]
LIST.sort(key=lambda x: int(x.split(']')[1]))
print(LIST)
更好的方法是先解析字符串。例如:
from collections import namedtuple
import re
FruitTuple = namedtuple('FruitTuple', ['fruit', 'color', 'num1', 'num2', 'num3'])
unparsed_list = [
'Apple, Orange[123 431]43351',
'Banana, Cherry[141 421]23423',
'Coconut, Mango[23 12312]232342'
]
split_list = [re.search('(\\w+), (\\w+)\\[(\\d+) (\\d+)\\](\\d+)', x).groups() for x in unparsed_list]
fruit_list = [FruitTuple(*x) for x in split_list]
fruit_list.sort(key=lambda x: int(x.num2))
print(fruit_list)
产地:
[FruitTuple(fruit ='Banana',color ='Cherry',num1 ='141',num2 ='421',num3 ='23423'),FruitTuple(fruit ='Apple',color ='Orange' ,num1 ='123',num2 ='431',num3 ='43351'),FruitTuple(fruit ='Coconut',color ='Mango',num1 ='23',num2 ='12312',num3 ='232342 “)]